Convert the strength of selected materials given in the accompanying table from MPa to ksi, where 1,000 lbf/in2 = 1 ksi.Material Ultimate Strength (Mpa) Ultimate Strength (ksi)Steel Machine 550–860 smaller value larger value Spring 700–1,900 smaller value larger value Stainless 400–1,000 smaller value larger value Tool 900 Structural Steel 340–830 smaller value larger value Titanium Alloys 900–1,200 smaller value larger value Wood (Bending) Douglas Fir 50–80 smaller value larger value Oak 50–100 smaller value larger value Southern Pine 50–100 smaller value larger value Other Aluminum Alloys 100–550 smaller value larger value Concrete (Compression) 10–70 smaller value larger value
Question
Convert the strength of selected materials given in the accompanying table from MPa to ksi, where 1,000 lbf/in2 = 1 ksi.Material Ultimate Strength (Mpa) Ultimate Strength (ksi)Steel Machine 550–860 smaller value larger value Spring 700–1,900 smaller value larger value Stainless 400–1,000 smaller value larger value Tool 900 Structural Steel 340–830 smaller value larger value Titanium Alloys 900–1,200 smaller value larger value Wood (Bending) Douglas Fir 50–80 smaller value larger value Oak 50–100 smaller value larger value Southern Pine 50–100 smaller value larger value Other Aluminum Alloys 100–550 smaller value larger value Concrete (Compression) 10–70 smaller value larger value
Solution
To convert the strength of materials from MPa to ksi, you need to know that 1 MPa is approximately equal to 0.1450377377 ksi.
Here are the conversions for the materials listed:
-
Steel Machine:
- Smaller value: 550 MPa * 0.1450377377 = 79.77 ksi
- Larger value: 860 MPa * 0.1450377377 = 124.73 ksi
-
Spring:
- Smaller value: 700 MPa * 0.1450377377 = 101.53 ksi
- Larger value: 1900 MPa * 0.1450377377 = 275.57 ksi
-
Stainless:
- Smaller value: 400 MPa * 0.1450377377 = 58.02 ksi
- Larger value: 1000 MPa * 0.1450377377 = 145.04 ksi
-
Tool:
- Value: 900 MPa * 0.1450377377 = 130.53 ksi
-
Structural Steel:
- Smaller value: 340 MPa * 0.1450377377 = 49.31 ksi
- Larger value: 830 MPa * 0.1450377377 = 120.38 ksi
-
Titanium Alloys:
- Smaller value: 900 MPa * 0.1450377377 = 130.53 ksi
- Larger value: 1200 MPa * 0.1450377377 = 174.05 ksi
-
Wood (Bending) Douglas Fir:
- Smaller value: 50 MPa * 0.1450377377 = 7.25 ksi
- Larger value: 80 MPa * 0.1450377377 = 11.60 ksi
-
Oak:
- Smaller value: 50 MPa * 0.1450377377 = 7.25 ksi
- Larger value: 100 MPa * 0.1450377377 = 14.50 ksi
-
Southern Pine:
- Smaller value: 50 MPa * 0.1450377377 = 7.25 ksi
- Larger value: 100 MPa * 0.1450377377 = 14.50 ksi
-
Other Aluminum Alloys:
- Smaller value: 100 MPa * 0.1450377377 = 14.50 ksi
- Larger value: 550 MPa * 0.1450377377 = 79.77 ksi
-
Concrete (Compression):
- Smaller value: 10 MPa * 0.1450377377 = 1.45 ksi
- Larger value: 70 MPa * 0.1450377377 = 10.15 ksi
Please note that these values are approximations.
Similar Questions
Determine the minimum material yield strength required based on a limit strength design if a factor of safety of 1.5 is required. Provide your answer in units of MPa to 2 decimal places.
The load for the beam in the image (b) below is X=14.1 KN. Image (a) represents the cross-section of the beam. Determine the maximum tensile bending stress in the beam in MPa.
A steel sheet with inhomogeneity factor of f0 = 0.995 is deforming in balanced biaxial tension with σ1a and σ2a as principal stresses in the uniform region ‘A’. What is the major principal stress σ1b in the groove ‘B’ at a small effective plastic strain of 0.05 if the material follows σ̅σ̅= 600 (0.004 +ε̅ε̅ )0.2 MPa hardening model. Find the value in MPa.
For a steel sheet with k = 500 MPa, ε0= 0.05, n = 0.30, the true strain at necking would be ___________ if tensile necking begins at the maximum load. Choose the best from the choices. (a) 0.25 (b) 0.30 (c) 0.2 (d) 0.15
Which is NOT one of the mechanical properties that define a material.Group of answer choicesinsulation valuetensile strengthpermeabilityductility
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.