The threshold frequency of a metal with work function 6.63 eV is
Question
The threshold frequency of a metal with work function 6.63 eV is
Solution
The threshold frequency (f) of a metal can be calculated using the formula:
f = Φ/h
where: Φ is the work function of the metal, and h is the Planck's constant.
Given that the work function Φ is 6.63 eV, we first need to convert this energy from electronvolts (eV) to joules (J) because the Planck's constant h is given in J.s. We know that 1 eV = 1.6 x 10^-19 J. So,
Φ = 6.63 eV = 6.63 * 1.6 x 10^-19 J = 1.0608 x 10^-18 J
The value of Planck's constant h is approximately 6.63 x 10^-34 J.s. Now we can substitute these values into the formula:
f = Φ/h = (1.0608 x 10^-18 J) / (6.63 x 10^-34 J.s) = 1.6 x 10^15 Hz
So, the threshold frequency of the metal is 1.6 x 10^15 Hz.
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