The molarity of 98% by wt. H2SO4 (d = 1.8 g/ml) is

To find the molarity of 98% by weight H2SO4, we need to first calculate the density of the solution.

Given that the density of the solution is 1.8 g/ml, we can convert this to g/cm^3 by dividing by 1000.

Density = 1.8 g/ml = 1.8 g/cm^3

Next, we need to calculate the molar mass of H2SO4.

The molar mass of H2SO4 can be calculated by adding up the atomic masses of each element in the compound.

H2SO4 = (2 * 1.01 g/mol) + (1 * 32.07 g/mol) + (4 * 16.00 g/mol) = 98.09 g/mol

Now, we can calculate the molarity using the formula:

Molarity (M) = (weight percent * density * 10) / (molar mass)

Weight percent = 98% Density = 1.8 g/cm^3 Molar mass = 98.09 g/mol

Molarity (M) = (98% * 1.8 g/cm^3 * 10) / (98.09 g/mol)

Molarity (M) = 17.64 M

Therefore, the molarity of 98% by weight H2SO4 is 17.64 M.