Which one of the following is correct syntax for opening a file.a.FILE *fopen(const *filename, const char *mode)b.FILE *fopen(const *filename)c.FILE *open(const *filename, const char *mode)d.FILE open(const*filename)Clear my choice
Question
Which one of the following is correct syntax for opening a file.a.FILE *fopen(const *filename, const char *mode)b.FILE *fopen(const *filename)c.FILE *open(const *filename, const char mode)d.FILE open(constfilename)Clear my choice
Solution
To determine the correct syntax for opening a file, let's analyze each option:
a. FILE *fopen(const *filename, const char *mode) This option seems to be the correct syntax for opening a file. It uses the fopen function, which is commonly used for file operations. The function takes two parameters: filename, which is a pointer to a constant character, and mode, which is a pointer to a constant character array.
b. FILE *fopen(const *filename) This option is missing the second parameter, mode, which is required to specify the file opening mode. Therefore, this syntax is incorrect.
c. FILE *open(const *filename, const char *mode) This option uses the open function instead of fopen. While the open function can also be used to open files, it is not the standard function for file operations in most programming languages. Therefore, this syntax is incorrect.
d. FILE open(constfilename) This option is missing the asterisk () before the filename parameter, which indicates that it is a pointer. Additionally, it is missing the second parameter, mode. Therefore, this syntax is incorrect.
Based on the analysis, the correct syntax for opening a file is option a. FILE *fopen(const *filename, const char *mode).
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