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Write a program that finds the smallest even integer that is divisible by 13 and by 16 whosesquare root is greater than 120. Use a loop in the program. The loop should start from 1 andstop when the number is found. The program prints the message “The required number is:”and then displays the number.

Question

Write a program that finds the smallest even integer that is divisible by 13 and by 16 whosesquare root is greater than 120. Use a loop in the program. The loop should start from 1 andstop when the number is found. The program prints the message “The required number is:”and then displays the number.

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Solution

Here is a Python program that fulfills your requirements:

import math

# Start the loop from 1
i = 1

while True:
    # Check if the number is even, divisible by 13 and 16
    if i % 2 == 0 and i % 13 == 0 and i % 16 == 0:
        # Check if the square root of the number is greater than 120
        if math.sqrt(i) > 120:
            print("The required number is:", i)
            break
    i += 1

This program starts a loop from 1 and checks each number to see if it is even and divisible by 13 and 16. If it is, it then checks if the square root of the number is greater than 120. If all these conditions are met, it prints the number and breaks the loop.

This problem has been solved

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Find the least number exactly divisible by 12, 15, 20 and 27.

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