The correct sequence of events during bacteriophage infection of a bacterial cell is(A) landing → attachment → tail contraction → penetration and unplugging → DNAejection(B) attachment → landing → penetration and unplugging → tail contraction → DNAejection(C) landing → tail contraction → attachment → DNA ejection → penetration andunplugging(D) attachment → tail contraction → landing → penetration and unplugging → DNAejection
Question
The correct sequence of events during bacteriophage infection of a bacterial cell is(A) landing → attachment → tail contraction → penetration and unplugging → DNAejection(B) attachment → landing → penetration and unplugging → tail contraction → DNAejection(C) landing → tail contraction → attachment → DNA ejection → penetration andunplugging(D) attachment → tail contraction → landing → penetration and unplugging → DNAejection
Solution
The correct sequence of events during bacteriophage infection of a bacterial cell is (A) landing → attachment → tail contraction → penetration and unplugging → DNA ejection.
Here's the step-by-step process:
- Landing: The bacteriophage comes into contact with the bacterial cell.
- Attachment: The bacteriophage attaches itself to the bacterial cell. This is usually done through specific binding between proteins on the bacteriophage and receptors on the bacterial cell.
- Tail contraction: After attachment, the bacteriophage's tail contracts, which is a mechanism to penetrate the bacterial cell wall.
- Penetration and unplugging: The bacteriophage injects its DNA into the bacterial cell by penetrating the cell wall. The 'unplugging' refers to the release of the bacteriophage DNA into the bacterial cell.
- DNA ejection: The bacteriophage's DNA is injected into the bacterial cell, where it will use the cell's machinery to replicate itself.
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