In a geometric progression, the ratio of any term to the previous term is constant. Let's denote this ratio as r.

We know that the 2nd term is 9 and the 6th term is 729. This means that multiplying the 2nd term by r four times gives us the 6th term. In other words, (9 * r^4) = 729.

Solving this equation for r gives us r = 3.

Now, to find the 4th term, we multiply the 2nd term by r two times. This gives us (9 * 3^2) = 81.

So, the 4th term of the geometric progression is 81. The correct answer is d. 81.

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In a geometric progression, the ratio of any term to the previous term is constant. Let's denote this ratio as r.

We know that the 2nd term is 9 and the 6th term is 729. This means that multiplying the 2nd term by r four times gives us the 6th term. In other words, (9 * r^4) = 729.

Solving this equation for r gives us r = 3.

Now, to find the 4th term, we multiply the 2nd term by r two times. This gives us (9 * 3^2) = 81.

So, the 4th term of the geometric progression is 81. The correct answer is d. 81.

Knowee AI · Accepted Answer

In a geometric progression, the ratio of any term to the previous term is constant. Let's denote this ratio as r.

We know that the 2nd term is 9 and the 6th term is 729. This means that multiplying the 2nd term by r four times gives us the 6th term. In other words, (9 * r^4) = 729.

Solving this equation for r gives us r = 3.

Now, to find the 4th term, we multiply the 2nd term by r two times. This gives us (9 * 3^2) = 81.

So, the 4th term of the geometric progression is 81. The correct answer is d. 81.

In a geometric progression consisting of real numbers, the 2nd term is 9 and the 6th term is 729. What is the 4th term?a.27b.- 27c.- 81d.81

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