You are given 2 arrays A and B of same size N. A pair is said to be a valid if and only if i < j, A[i] == B[j] and A[j] == B[i]. You have to count total number of valid pairs.Input FormatFirst line of input contains T - number of test cases. First line of each test case contains N - size of the array. The second and third line of each test case contains N integers - elements of the array A and B.Output FormatFor each test case, print the count of number of valid pairs, separated by newline.Constraints30 points1 <= N <= 10370 points1 <= N <= 105General Constraints1 <= T <= 1000 <= A[i], B[i] <= 109ExampleInput231 2 33 2 151 3 7 9 93 1 9 7 7Output13ExplanationTest Case 1:There is only one valid pair - (0, 2). This is because A[0] == B[2] and A[2] == B[0].Test Case 2:There are 3 valid pairs - (0, 1), (2, 3), (2, 4). For example (0, 1) is valid because A[0] == B[1] and A[1] == B[0].
Question
You are given 2 arrays A and B of same size N. A pair is said to be a valid if and only if i < j, A[i] == B[j] and A[j] == B[i]. You have to count total number of valid pairs.Input FormatFirst line of input contains T - number of test cases. First line of each test case contains N - size of the array. The second and third line of each test case contains N integers - elements of the array A and B.Output FormatFor each test case, print the count of number of valid pairs, separated by newline.Constraints30 points1 <= N <= 10370 points1 <= N <= 105General Constraints1 <= T <= 1000 <= A[i], B[i] <= 109ExampleInput231 2 33 2 151 3 7 9 93 1 9 7 7Output13ExplanationTest Case 1:There is only one valid pair - (0, 2). This is because A[0] == B[2] and A[2] == B[0].Test Case 2:There are 3 valid pairs - (0, 1), (2, 3), (2, 4). For example (0, 1) is valid because A[0] == B[1] and A[1] == B[0].
Solution
To solve this problem, you can use a hash map to store the frequency of each pair of numbers in arrays A and B. Here are the steps:
- Initialize a hash map.
- Iterate over the
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