The output of the given Python code will be 15.

Here's the step by step explanation:

1. The variable `x` is first set to 12.
2. The function `fun()` is then called.
3. Inside the function `fun()`, a new local variable `x` is defined and set to 15. This local variable `x` is different from the global variable `x` defined outside the function.
4. The `print(x)` statement inside the function `fun()` will print the value of the local variable `x`, which is 15.
5. After the function call, the global variable `x` still remains 12, but it is not printed.

So, the correct answer is 15.

Question

The output of the given Python code will be 15.

Here's the step by step explanation:

1. The variable `x` is first set to 12.
2. The function `fun()` is then called. 
3. Inside the function `fun()`, a new local variable `x` is defined and set to 15. This local variable `x` is different from the global variable `x` defined outside the function.
4. The `print(x)` statement inside the function `fun()` will print the value of the local variable `x`, which is 15.
5. After the function call, the global variable `x` still remains 12, but it is not printed.

So, the correct answer is 15.

Knowee AI · Accepted Answer

The output of the given Python code will be 15.

Here's the step by step explanation:

1. The variable `x` is first set to 12.
2. The function `fun()` is then called. 
3. Inside the function `fun()`, a new local variable `x` is defined and set to 15. This local variable `x` is different from the global variable `x` defined outside the function.
4. The `print(x)` statement inside the function `fun()` will print the value of the local variable `x`, which is 15.
5. After the function call, the global variable `x` still remains 12, but it is not printed.

So, the correct answer is 15.

What will be the output of the following Python code?def fun(): x=15 print(x)x=12fun()Options: Pick one correct answer from belowError151215 12

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