To determine which of the given options is NOT a topological ordering, we need to understand what a topological ordering is.

A topological ordering of a directed acyclic graph (DAG) is a linear ordering of its vertices such that for every directed edge (u, v), vertex u comes before vertex v in the ordering. In other words, it is a sequence of vertices where each vertex appears before its adjacent vertices.

Let's analyze each option:

1 3 2 4 6 5: This ordering seems to satisfy the topological ordering property. Vertex 1 comes before vertices 3 and 2, vertex 3 comes before vertex 2, vertex 2 comes before vertex 4, vertex 4 comes before vertex 6, and vertex 6 comes before vertex 5. So, this option could be a valid topological ordering.

1 3 2 4 5 6: This ordering also seems to satisfy the topological ordering property. Vertex 1 comes before vertices 3 and 2, vertex 3 comes before vertex 2, vertex 2 comes before vertex 4, vertex 4 comes before vertex 5, and vertex 5 comes before vertex 6. So, this option could be a valid topological ordering.

3 2 4 1 6 5: This ordering violates the topological ordering property. Vertex 3 comes before vertex 2, which is correct. But then vertex 2 comes before vertex 4, which is incorrect. In a valid topological ordering, vertex 4 should come before vertex 2. Therefore, this option is NOT a valid topological ordering.

1 2 3 4 5 6: This ordering seems to satisfy the topological ordering property. Vertex 1 comes before vertex 2, vertex 2 comes before vertex 3, vertex 3 comes before vertex 4, vertex 4 comes before vertex 5, and vertex 5 comes before vertex 6. So, this option could be a valid topological ordering.

Based on the analysis, the option "3 2 4 1 6 5" is NOT a valid topological ordering.

Question

To determine which of the given options is NOT a topological ordering, we need to understand what a topological ordering is.

A topological ordering of a directed acyclic graph (DAG) is a linear ordering of its vertices such that for every directed edge (u, v), vertex u comes before vertex v in the ordering. In other words, it is a sequence of vertices where each vertex appears before its adjacent vertices.

Let's analyze each option:

1 3 2 4 6 5: This ordering seems to satisfy the topological ordering property. Vertex 1 comes before vertices 3 and 2, vertex 3 comes before vertex 2, vertex 2 comes before vertex 4, vertex 4 comes before vertex 6, and vertex 6 comes before vertex 5. So, this option could be a valid topological ordering.

1 3 2 4 5 6: This ordering also seems to satisfy the topological ordering property. Vertex 1 comes before vertices 3 and 2, vertex 3 comes before vertex 2, vertex 2 comes before vertex 4, vertex 4 comes before vertex 5, and vertex 5 comes before vertex 6. So, this option could be a valid topological ordering.

3 2 4 1 6 5: This ordering violates the topological ordering property. Vertex 3 comes before vertex 2, which is correct. But then vertex 2 comes before vertex 4, which is incorrect. In a valid topological ordering, vertex 4 should come before vertex 2. Therefore, this option is NOT a valid topological ordering.

1 2 3 4 5 6: This ordering seems to satisfy the topological ordering property. Vertex 1 comes before vertex 2, vertex 2 comes before vertex 3, vertex 3 comes before vertex 4, vertex 4 comes before vertex 5, and vertex 5 comes before vertex 6. So, this option could be a valid topological ordering.

Based on the analysis, the option "3 2 4 1 6 5" is NOT a valid topological ordering.

Knowee AI · Accepted Answer

To determine which of the given options is NOT a topological ordering, we need to understand what a topological ordering is.

A topological ordering of a directed acyclic graph (DAG) is a linear ordering of its vertices such that for every directed edge (u, v), vertex u comes before vertex v in the ordering. In other words, it is a sequence of vertices where each vertex appears before its adjacent vertices.

Let's analyze each option:

1 3 2 4 6 5: This ordering seems to satisfy the topological ordering property. Vertex 1 comes before vertices 3 and 2, vertex 3 comes before vertex 2, vertex 2 comes before vertex 4, vertex 4 comes before vertex 6, and vertex 6 comes before vertex 5. So, this option could be a valid topological ordering.

1 3 2 4 5 6: This ordering also seems to satisfy the topological ordering property. Vertex 1 comes before vertices 3 and 2, vertex 3 comes before vertex 2, vertex 2 comes before vertex 4, vertex 4 comes before vertex 5, and vertex 5 comes before vertex 6. So, this option could be a valid topological ordering.

3 2 4 1 6 5: This ordering violates the topological ordering property. Vertex 3 comes before vertex 2, which is correct. But then vertex 2 comes before vertex 4, which is incorrect. In a valid topological ordering, vertex 4 should come before vertex 2. Therefore, this option is NOT a valid topological ordering.

1 2 3 4 5 6: This ordering seems to satisfy the topological ordering property. Vertex 1 comes before vertex 2, vertex 2 comes before vertex 3, vertex 3 comes before vertex 4, vertex 4 comes before vertex 5, and vertex 5 comes before vertex 6. So, this option could be a valid topological ordering.

Based on the analysis, the option "3 2 4 1 6 5" is NOT a valid topological ordering.

Consider the DAG with V = {1, 2, 3, 4, 5, 6}, shown below. Which of the following is NOT a topological ordering?Marks : 1Negative Marks : 0Answer here1 3 2 4 6 51 3 2 4 5 63 2 4 1 6 51 2 3 4 5 6

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