To find a regular expression for (L1⋃ L2)∗L2, we first need to understand what each of these languages represent.

1. L1 = L(ab*aa): This language represents all strings that start with 'a', followed by zero or more 'b's, and ending with 'aa'.

2. L2 = L(a*bba*): This language represents all strings that start with zero or more 'a's, followed by 'bb', and ending with zero or more 'a's.

Now, let's find the regular expression for (L1⋃ L2)∗L2:

1. L1⋃ L2: This represents the union of L1 and L2, which means it includes all strings that are either in L1 or L2. The regular expression for this would be (ab*aa | a*bba*).

2. (L1⋃ L2)∗: This represents zero or more occurrences of strings that are either in L1 or L2. The regular expression for this would be (ab*aa | a*bba*)*.

3. (L1⋃ L2)∗L2: This represents zero or more occurrences of strings that are either in L1 or L2, followed by a string that is in L2. The regular expression for this would be (ab*aa | a*bba*)*a*bba*.

So, the regular expression for (L1⋃ L2)∗L2 is (ab*aa | a*bba*)*a*bba*.

Question

To find a regular expression for (L1⋃ L2)∗L2, we first need to understand what each of these languages represent.

1. L1 = L(ab*aa): This language represents all strings that start with 'a', followed by zero or more 'b's, and ending with 'aa'.

2. L2 = L(a*bba*): This language represents all strings that start with zero or more 'a's, followed by 'bb', and ending with zero or more 'a's.

Now, let's find the regular expression for (L1⋃ L2)∗L2:

1. L1⋃ L2: This represents the union of L1 and L2, which means it includes all strings that are either in L1 or L2. The regular expression for this would be (ab*aa | a*bba*).

2. (L1⋃ L2)∗: This represents zero or more occurrences of strings that are either in L1 or L2. The regular expression for this would be (ab*aa | a*bba*)*.

3. (L1⋃ L2)∗L2: This represents zero or more occurrences of strings that are either in L1 or L2, followed by a string that is in L2. The regular expression for this would be (ab*aa | a*bba*)*a*bba*.

So, the regular expression for (L1⋃ L2)∗L2 is (ab*aa | a*bba*)*a*bba*.

Knowee AI · Accepted Answer

To find a regular expression for (L1⋃ L2)∗L2, we first need to understand what each of these languages represent.

1. L1 = L(ab*aa): This language represents all strings that start with 'a', followed by zero or more 'b's, and ending with 'aa'.

2. L2 = L(a*bba*): This language represents all strings that start with zero or more 'a's, followed by 'bb', and ending with zero or more 'a's.

Now, let's find the regular expression for (L1⋃ L2)∗L2:

1. L1⋃ L2: This represents the union of L1 and L2, which means it includes all strings that are either in L1 or L2. The regular expression for this would be (ab*aa | a*bba*).

2. (L1⋃ L2)∗: This represents zero or more occurrences of strings that are either in L1 or L2. The regular expression for this would be (ab*aa | a*bba*)*.

3. (L1⋃ L2)∗L2: This represents zero or more occurrences of strings that are either in L1 or L2, followed by a string that is in L2. The regular expression for this would be (ab*aa | a*bba*)*a*bba*.

So, the regular expression for (L1⋃ L2)∗L2 is (ab*aa | a*bba*)*a*bba*.

Let L1=L(ab∗aa), L2=L(a∗bba∗). Find a regular expression for (L1⋃ L2)∗L2

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