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public void display() { if(size == 0) System.out.println("underflow"); else { Node current = first; while(current != null) { System.out.println(current.getEle()); current = current.getNext(); } }}

Question

public void display() { if(size == 0) System.out.println("underflow"); else { Node current = first; while(current != null) { System.out.println(current.getEle()); current = current.getNext(); } }}

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Solution

This is a Java method named display(). Here's a step-by-step explanation of what it does:

  1. The method display() is declared as public, which means it can be accessed from any class.

  2. Inside the method, there's an if-else statement that checks the size of a data structure (possibly a linked list, given the context).

  3. If the size is 0, it prints "underflow" to the console. This typically means that an operation was attempted on an empty data structure.

  4. If the size is not 0, it enters the else block. Here, a Node object named current is created and initialized with the value of first. This first is likely the head of the linked list.

  5. Then, a while loop is initiated which continues as long as current is not null. Inside the loop, it prints the element stored in current and then moves current to the next node in the list.

  6. This process continues until current becomes null, i.e., until it has traversed all the nodes in the list. At this point, the method ends.

In summary, this method is used to print all the elements in a linked list from the first node to the last.

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