Show below is the combustion of benzene, C6H6.C6H6 + O2--> CO2 + H2O1,004 grams of benzene are supplied and some excess air. If3,105 grams of carbon dioxide are produced, compute for the percentage yield.Write your final answer in two decimal places.Use the following mass numbers:C - 12 g/molH - 1 g/molO - 16 g/mol
Question
Show below is the combustion of benzene, C6H6.C6H6 + O2--> CO2 + H2O1,004 grams of benzene are supplied and some excess air. If3,105 grams of carbon dioxide are produced, compute for the percentage yield.Write your final answer in two decimal places.Use the following mass numbers:C - 12 g/molH - 1 g/molO - 16 g/mol
Solution
To calculate the percentage yield, we first need to determine the theoretical yield of CO2 from the combustion of benzene.
Step 1: Calculate the molar mass of benzene (C6H6) The molar mass of benzene is (612 g/mol C) + (61 g/mol H) = 78 g/mol.
Step 2: Calculate the moles of benzene used The moles of benzene used is 1,004 g / 78 g/mol = 12.87 mol.
Step 3: Determine the stoichiometry of the reaction From the balanced chemical equation, we can see that 1 mol of benzene produces 6 mol of CO2.
Step 4: Calculate the theoretical yield of CO2 The theoretical yield of CO2 is 12.87 mol * 6 = 77.22 mol.
Step 5: Convert the theoretical yield to grams The molar mass of CO2 is (12 g/mol C) + (2*16 g/mol O) = 44 g/mol. So, the theoretical yield in grams is 77.22 mol * 44 g/mol = 3,397.68 g.
Step 6: Calculate the percentage yield The percentage yield is (actual yield / theoretical yield) * 100%. The actual yield is given as 3,105 g. So, the percentage yield is (3,105 g / 3,397.68 g) * 100% = 91.37%.
So, the percentage yield of the reaction is 91.37%.
Similar Questions
Show below is the combustion of hexane, C6H14.C6H14 + O2--> CO2 + H2OIf 444 grams of hexane and 2,038 grams of air are supplied, compute for the percentage excess.Write your final answer in two decimal places.Use the following mass numbers:C - 12 g/molH - 1 g/molO - 16 g/mol
A mass of 8.15 g C2H4(g) reacts with excess oxygen. If 16.2 g CO2(g) is collected, what is the percent yield of the reaction? C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(g)Group of answer choices41.0%31.7%57.1%63.3%
Given:C2H6(g) + O2(g) ⟶ CO2(g) + H2O(g)If 319 grams of ethane and 1,597 grams of air are supplied, compute for the % excess.Write your final answer in two decimal places.Use the following mass numbers:O - 16C - 12H - 1
If 4.750 g of CO2(g) was obtained from the combustion of 1.638 g of propane, what was the percent yield?
The combustion of hexyne, C6H10 is represented by the given equation:C6H10 + O2 --> CO2 + H2OIf 403 grams of C6H10 is available. If all C6H10 will be fully consumed, how many grams of CO2 will be produced for complete combustion assuming no excess O2 is supplied?Write your final answer in two decimal places.Use the following mass numbers:C - 12 g/molH - 1 g/molO - 16 g/mol
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.