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Using s,p,d,f notation, give orbital designation for:(a) n = 2, l =1, ml = -1, ms = + ½(b) n = 3, l=2, ml = -2, ms = + ½(c) n = 3, l=1, ml = -1, ms = + ½(d) n = 4, l=0, ml = 0, ms = + ½

Question

Using s,p,d,f notation, give orbital designation for:(a) n = 2, l =1, ml = -1, ms = + ½(b) n = 3, l=2, ml = -2, ms = + ½(c) n = 3, l=1, ml = -1, ms = + ½(d) n = 4, l=0, ml = 0, ms = + ½

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Solution

(a) For the given values of n = 2, l = 1, ml = -1, and ms = + ½, we can determine the orbital designation using the s,p,d,f notation.

The orbital designation is determined by the values of l and ml.

In this case, l = 1 corresponds to the p orbital.

The ml value of -1 corresponds to the px orbital.

Therefore, the orbital designation for (a) is 2p.

(b) For the given values of n = 3, l = 2, ml = -2, and ms = + ½, we can determine the orbital designation using the s,p,d,f notation.

The orbital designation is determined by the values of l and ml.

In this case, l = 2 corresponds to the d orbital.

The ml value of -2 corresponds to the dxy orbital.

Therefore, the orbital designation for (b) is 3dxy.

(c) For the given values of n = 3, l = 1, ml = -1, and ms = + ½, we can determine the orbital designation using the s,p,d,f notation.

The orbital designation is determined by the values of l and ml.

In this case, l = 1 corresponds to the p orbital.

The ml value of -1 corresponds to the px orbital.

Therefore, the orbital designation for (c) is 3px.

(d) For the given values of n = 4, l = 0, ml = 0, and ms = + ½, we can determine the orbital designation using the s,p,d,f notation.

The orbital designation is determined by the values of l and ml.

In this case, l = 0 corresponds to the s orbital.

The ml value of 0 corresponds to the s orbital.

Therefore, the orbital designation for (d) is 4s.

This problem has been solved

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