elect the correct answerWhat will be the output of the following Java code?class Main{ public static void main(String args[]) { Thread t = Thread.currentThread(); t.setName("New Thread"); System.out.println(t); }}OptionsThread[main,5,main]Thread[New Thread,5]Thread[5,main]Thread[New Thread,5,main]
Question
elect the correct answerWhat will be the output of the following Java code?class Main{ public static void main(String args[]) { Thread t = Thread.currentThread(); t.setName("New Thread"); System.out.println(t); }}OptionsThread[main,5,main]Thread[New Thread,5]Thread[5,main]Thread[New Thread,5,main]
Solution
The correct answer is: Thread[New Thread,5,main]
Here's why:
In the given Java code, a reference to the current thread is obtained by calling the static method Thread.currentThread(). This reference is stored in the variable 't'.
Then, the name of the current thread is changed to "New Thread" using the setName() method.
Finally, when the thread is printed, it will display the thread's name ("New Thread"), its priority (5, which is the default priority), and the name of the group to which this thread belongs ("main").
So, the output will be: Thread[New Thread,5,main]
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