Given an array nums of n integers, return an array of all the unique quadruplets [nums[a], nums[b], nums[c], nums[d]] such that:0 <= a, b, c, d < na, b, c, and d are distinct.nums[a] + nums[b] + nums[c] + nums[d] == targetYou may return the answer in any order. Example 1:Input: nums = [1,0,-1,0,-2,2], target = 0Output: [[-2,-1,1,2],[-2,0,0,2],[-1,0,0,1]]Example 2:Input: nums = [2,2,2,2,2], target = 8Output: [[2,2,2,2]] Constraints:1 <= nums.length <= 200-109 <= nums[i] <= 109-109 <= target <= 109
Question
Given an array nums of n integers, return an array of all the unique quadruplets [nums[a], nums[b], nums[c], nums[d]] such that:0 <= a, b, c, d < na, b, c, and d are distinct.nums[a] + nums[b] + nums[c] + nums[d] == targetYou may return the answer in any order. Example 1:Input: nums = [1,0,-1,0,-2,2], target = 0Output: [[-2,-1,1,2],[-2,0,0,2],[-1,0,0,1]]Example 2:Input: nums = [2,2,2,2,2], target = 8Output: [[2,2,2,2]] Constraints:1 <= nums.length <= 200-109 <= nums[i] <= 109-109 <= target <= 109
Solution 1
This problem is asking to find all unique quadruplets in the array that sum up to the target value. Here is a step-by-step solution using Python:
- First, sort the input array. This will allow us to easily move around the array and avoid duplicates.
nums.sort()
- Initialize an empty list to store the result.
result = []
- Create four nested loops to generate all combinations of four numbers. The outermost loop runs from 0 to the length of the array. The second loop runs from the current index of the outer loop plus 1. The third and fourth loops use two pointers, one starting from the current index of
Solution 2
This problem is asking to find all unique quadruplets in the array that sum up to the target value. Here is a step-by-step solution in Python:
- First, sort the input array. This will allow us to easily move around the array and avoid duplicates.
nums.sort()
- Initialize an empty list to store the quadruplets.
result = []
- Create four nested loops to generate all possible quadruplets. The outermost loop runs from 0 to the length of the array. The second loop runs from the current index of the outer loop plus 1 to the length of the array. The third and fourth loops use two pointers, one starting from the current index of the second loop plus 1 and the other starting from the end of the array.
Similar Questions
Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0.Notice that the solution set must not contain duplicate triplets. Example 1:Input: nums = [-1,0,1,2,-1,-4]Output: [[-1,-1,2],[-1,0,1]]Explanation: nums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0.nums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0.nums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0.The distinct triplets are [-1,0,1] and [-1,-1,2].Notice that the order of the output and the order of the triplets does not matter.Example 2:Input: nums = [0,1,1]Output: []Explanation: The only possible triplet does not sum up to 0.Example 3:Input: nums = [0,0,0]Output: [[0,0,0]]Explanation: The only possible triplet sums up to 0. Constraints:3 <= nums.length <= 3000-105 <= nums[i] <= 105
Given an array A of integers and another number K. Find all the unique quadruple from the given array that sums up to K.Also note that all the quadruples which you return should be internally sorted, ie for any quadruple [q1, q2, q3, q4] the following should follow: q1 <= q2 <= q3 <= q4.
Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears once or twice, return an array of all the integers that appears twice.You must write an algorithm that runs in O(n) time and uses only constant extra space. Example 1:Input: nums = [4,3,2,7,8,2,3,1]Output: [2,3]Example 2:Input: nums = [1,1,2]Output: [1]Example 3:Input: nums = [1]Output: [] Constraints:
442. Find All Duplicates in an ArrayMediumTopicsCompaniesGiven an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears once or twice, return an array of all the integers that appears twice.You must write an algorithm that runs in O(n) time and uses only constant extra space. Example 1:Input: nums = [4,3,2,7,8,2,3,1]Output: [2,3]Example 2:Input: nums = [1,1,2]Output: [1]Example 3:Input: nums = [1]Output: [] Constraints:n == nums.length1 <= n <= 1051 <= nums[i] <= nEach element in nums appears once or twice.
You are given an integer array nums. The uniqueness array of nums is the sorted array that contains the number of distinct elements of all the subarrays of nums. In other words, it is a sorted array consisting of distinct(nums[i..j]), for all 0 <= i <= j < nums.length.Here, distinct(nums[i..j]) denotes the number of distinct elements in the subarray that starts at index i and ends at index j.Return the median of the uniqueness array of nums.Note that the median of an array is defined as the middle element of the array when it is sorted in non-decreasing order. If there are two choices for a median, the smaller of the two values is taken. Example 1:Input: nums = [1,2,3]Output: 1Explanation:The uniqueness array of nums is [distinct(nums[0..0]), distinct(nums[1..1]), distinct(nums[2..2]), distinct(nums[0..1]), distinct(nums[1..2]), distinct(nums[0..2])] which is equal to [1, 1, 1, 2, 2, 3]. The uniqueness array has a median of 1. Therefore, the answer is 1.Example 2:Input: nums = [3,4,3,4,5]Output: 2Explanation:The uniqueness array of nums is [1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3]. The uniqueness array has a median of 2. Therefore, the answer is 2.Example 3:Input: nums = [4,3,5,4]Output: 2Explanation:The uniqueness array of nums is [1, 1, 1, 1, 2, 2, 2, 3, 3, 3]. The uniqueness array has a median of 2. Therefore, the answer is 2. Constraints:1 <= nums.length <= 1051 <= nums[i] <= 105
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