If steam is passing through a throttling valve in a steady flow process, and we define the control volume as the valve:Question 2Select one:a.ΔmCV = 0, ΔECV = 0 and ΔSCV = 0b.ΔmCV > 0, ΔECV > 0 and ΔSCV > 0c.ΔmCV = 0, ΔECV > 0 and ΔSCV > 0d.ΔmCV = 0, ΔECV = 0 and ΔSCV > 0
Question
If steam is passing through a throttling valve in a steady flow process, and we define the control volume as the valve:Question 2Select one:a.ΔmCV = 0, ΔECV = 0 and ΔSCV = 0b.ΔmCV > 0, ΔECV > 0 and ΔSCV > 0c.ΔmCV = 0, ΔECV > 0 and ΔSCV > 0d.ΔmCV = 0, ΔECV = 0 and ΔSCV > 0
Solution
The correct answer is a. ΔmCV = 0, ΔECV = 0 and ΔSCV = 0.
Here's why:
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ΔmCV = 0: In a steady flow process, the mass flow rate entering the control volume (the valve) is equal to the mass flow rate leaving it. Therefore, there is no accumulation of mass within the control volume over time, which means the change in mass of the control volume (ΔmCV) is zero.
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ΔECV = 0: The energy change in the control volume is also zero. This is because the throttling process is assumed to be adiabatic (no heat transfer) and there is no work done (the valve doesn't move or change shape). Therefore, the total energy (internal, kinetic, potential) of the steam entering the valve is equal to the total energy of
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