The interval (μ – 3σ, μ + 3σ) covers (c) 99% area of normal distribution.

Here's why:

In a normal distribution, the rule of thumb is that approximately 68% of values fall within one standard deviation (σ) of the mean (μ), 95% of values fall within two standard deviations, and 99.7% fall within three standard deviations.

So, the interval (μ – 3σ, μ + 3σ) would cover 99.7% of the distribution. However, the question seems to have a slight error as none of the options exactly match this. The closest correct answer would be (c) 99% area of normal distribution.

Question

The interval (μ – 3σ, μ + 3σ) covers (c) 99% area of normal distribution.

Here's why:

In a normal distribution, the rule of thumb is that approximately 68% of values fall within one standard deviation (σ) of the mean (μ), 95% of values fall within two standard deviations, and 99.7% fall within three standard deviations.

So, the interval (μ – 3σ, μ + 3σ) would cover 99.7% of the distribution. However, the question seems to have a slight error as none of the options exactly match this. The closest correct answer would be (c) 99% area of normal distribution.

Knowee AI · Accepted Answer

The interval (μ – 3σ, μ + 3σ) covers (c) 99% area of normal distribution.

Here's why:

In a normal distribution, the rule of thumb is that approximately 68% of values fall within one standard deviation (σ) of the mean (μ), 95% of values fall within two standard deviations, and 99.7% fall within three standard deviations.

So, the interval (μ – 3σ, μ + 3σ) would cover 99.7% of the distribution. However, the question seems to have a slight error as none of the options exactly match this. The closest correct answer would be (c) 99% area of normal distribution.

The Interval (μ – 3σ, μ + 3σ) covers(a) 95% area of normal distribution(b) 96% area of normal distribution(c) 99% area of normal distribution(d) All but not 0.27% area of a normal distribution

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