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The population of of a town is 176000. If it increases at the rate of 5% per annum,what will be it’s population 2 years hence?

Question

The population of of a town is 176000. If it increases at the rate of 5% per annum,what will be it’s population 2 years hence?

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Solution

Step 1: Identify the initial population, the rate of increase, and the number of years. In this case, the initial population is 176,000, the rate of increase is 5% per annum, and the number of years is 2.

Step 2: Convert the rate of increase from a percentage to a decimal. To do this, divide the percentage by 100. So, 5% becomes 0.05.

Step 3: Calculate the population increase for the first year. To do this, multiply the initial population by the rate of increase. So, 176,000 * 0.05 = 8,800.

Step 4: Add the population increase for the first year to the initial population to get the population at the end of the first year. So, 176,000 + 8,800 = 184,800.

Step 5: Repeat steps 3 and 4 for the second year. So, 184,800 * 0.05 = 9,240, and 184,800 + 9,240 = 194,040.

So, the population of the town 2 years hence will be 194,040.

This problem has been solved

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