To find the order of magnitude of the kinetic energy of the electron, we can use the formula for kinetic energy:

K.E. = 1/2 mv^2

However, we don't have the velocity (v) of the electron. We do have the linear momentum (p), which is related to the mass (m) and velocity (v) by the formula:

p = mv

We can rearrange this formula to solve for v:

v = p/m

The mass of an electron (m) is approximately 9.11 × 10^-31 kg. The given linear momentum (p) is 4.0 × 10^-25 kg m s^-1. Substituting these values in:

v = (4.0 × 10^-25 kg m s^-1) / (9.11 × 10^-31 kg) = 4.39 × 10^5 m/s

Now we can substitute m and v into the kinetic energy formula:

K.E. = 1/2 (9.11 × 10^-31 kg) * (4.39 × 10^5 m/s)^2 = 8.8 × 10^-20 J

So, the order of magnitude of the kinetic energy of the electron is -20.

Question

To find the order of magnitude of the kinetic energy of the electron, we can use the formula for kinetic energy:

K.E. = 1/2 mv^2

However, we don't have the velocity (v) of the electron. We do have the linear momentum (p), which is related to the mass (m) and velocity (v) by the formula:

p = mv

We can rearrange this formula to solve for v:

v = p/m

The mass of an electron (m) is approximately 9.11 × 10^-31 kg. The given linear momentum (p) is 4.0 × 10^-25 kg m s^-1. Substituting these values in:

v = (4.0 × 10^-25 kg m s^-1) / (9.11 × 10^-31 kg) = 4.39 × 10^5 m/s

Now we can substitute m and v into the kinetic energy formula:

K.E. = 1/2 (9.11 × 10^-31 kg) * (4.39 × 10^5 m/s)^2 = 8.8 × 10^-20 J

So, the order of magnitude of the kinetic energy of the electron is -20.

Knowee AI · Accepted Answer

To find the order of magnitude of the kinetic energy of the electron, we can use the formula for kinetic energy:

K.E. = 1/2 mv^2

However, we don't have the velocity (v) of the electron. We do have the linear momentum (p), which is related to the mass (m) and velocity (v) by the formula:

p = mv

We can rearrange this formula to solve for v:

v = p/m

The mass of an electron (m) is approximately 9.11 × 10^-31 kg. The given linear momentum (p) is 4.0 × 10^-25 kg m s^-1. Substituting these values in:

v = (4.0 × 10^-25 kg m s^-1) / (9.11 × 10^-31 kg) = 4.39 × 10^5 m/s

Now we can substitute m and v into the kinetic energy formula:

K.E. = 1/2 (9.11 × 10^-31 kg) * (4.39 × 10^5 m/s)^2 = 8.8 × 10^-20 J

So, the order of magnitude of the kinetic energy of the electron is -20.

An electron has a linear momentum of 4.0 × 10-25 kg m s-1 . What is the order of magnitude ofthe kinetic energy of the electron?

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