To solve this problem, we can use the formula for compound interest, which is:

A = P (1 + r/n)^(nt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (in decimal)
n = number of times that interest is compounded per year
t = the number of years the money is invested for

In this case, we are trying to find the principal amount (P), so we need to rearrange the formula to solve for P:

P = A / (1 + r/n)^(nt)

We know that A = $81,000, r = 3.3% or 0.033 (in decimal), n = 1 (since the interest is compounded annually), and t = 16 years. Substituting these values into the formula, we get:

P = 81000 / (1 + 0.033/1)^(1*16)

Now, we just need to calculate the value of P.

P = 81000 / (1.033)^16
P = 81000 / 1.601033
P = $50,592.59

So, Santiago would need to invest approximately $50,593 (to the nearest ten dollars) for the value of the account to reach $81,000 in 16 years.

Question

To solve this problem, we can use the formula for compound interest, which is:

A = P (1 + r/n)^(nt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (in decimal)
n = number of times that interest is compounded per year
t = the number of years the money is invested for

In this case, we are trying to find the principal amount (P), so we need to rearrange the formula to solve for P:

P = A / (1 + r/n)^(nt)

We know that A = $81,000, r = 3.3% or 0.033 (in decimal), n = 1 (since the interest is compounded annually), and t = 16 years. Substituting these values into the formula, we get:

P = 81000 / (1 + 0.033/1)^(1*16)

Now, we just need to calculate the value of P.

P = 81000 / (1.033)^16
P = 81000 / 1.601033
P = $50,592.59

So, Santiago would need to invest approximately $50,593 (to the nearest ten dollars) for the value of the account to reach $81,000 in 16 years.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula for compound interest, which is:

A = P (1 + r/n)^(nt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (in decimal)
n = number of times that interest is compounded per year
t = the number of years the money is invested for

In this case, we are trying to find the principal amount (P), so we need to rearrange the formula to solve for P:

P = A / (1 + r/n)^(nt)

We know that A = $81,000, r = 3.3% or 0.033 (in decimal), n = 1 (since the interest is compounded annually), and t = 16 years. Substituting these values into the formula, we get:

P = 81000 / (1 + 0.033/1)^(1*16)

Now, we just need to calculate the value of P.

P = 81000 / (1.033)^16
P = 81000 / 1.601033
P = $50,592.59

So, Santiago would need to invest approximately $50,593 (to the nearest ten dollars) for the value of the account to reach $81,000 in 16 years.

Santiago is going to invest in an account paying an interest rate of 3.3% compounded annually. How much would Santiago need to invest, to the nearest ten dollars, for the value of the account to reach $81,000 in 16 years?

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