To answer this question, we need to look for all the occurrences of the digit '2' in the given arrangement that are both preceded and followed by an odd digit.

Let's go through the arrangement:

4 2 6 1 3 8 9 5 8 1 6 5 1 5 8 5 3 9 4 9 2 3 2 1 5 7 2 6 2 4 2 7 4

The first '2' is not preceded by an odd digit, so we skip it.

The second '2' is preceded by '9' (an odd digit) and followed by '3' (also an odd digit), so it counts.

The third '2' is preceded by '3' (an odd digit) but followed by '1' (an odd digit), so it also counts.

The fourth '2' is preceded by '7' (an odd digit) but followed by '6' (an even digit), so it doesn't count.

The fifth '2' is not preceded by an odd digit, so we skip it.

The sixth '2' is not followed by an odd digit, so we skip it.

So, there are 2 occurrences of '2' in the given arrangement that are both preceded and followed by an odd digit.

Question

To answer this question, we need to look for all the occurrences of the digit '2' in the given arrangement that are both preceded and followed by an odd digit.

Let's go through the arrangement:

4 2 6 1 3 8 9 5 8 1 6 5 1 5 8 5 3 9 4 9 2 3 2 1 5 7 2 6 2 4 2 7 4

The first '2' is not preceded by an odd digit, so we skip it.

The second '2' is preceded by '9' (an odd digit) and followed by '3' (also an odd digit), so it counts.

The third '2' is preceded by '3' (an odd digit) but followed by '1' (an odd digit), so it also counts.

The fourth '2' is preceded by '7' (an odd digit) but followed by '6' (an even digit), so it doesn't count.

The fifth '2' is not preceded by an odd digit, so we skip it.

The sixth '2' is not followed by an odd digit, so we skip it.

So, there are 2 occurrences of '2' in the given arrangement that are both preceded and followed by an odd digit.

Knowee AI · Accepted Answer