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Use half reaction potentials to predict whether the following reaction is spontaneous or non-spontaneous in an aqueous solution.2 H+(aq) + O2(g) ⟶ 2 H2(g) + Br2(aq)Group of answer choicesreaction is spontaneous becuase voltage potential is negativereaction is not spontaneous becuase the voltage potential is positivereaction is spontaneous becuase voltage potential is positivereaction is not spontaneous becuase the voltage potential is negative

Question

Use half reaction potentials to predict whether the following reaction is spontaneous or non-spontaneous in an aqueous solution.2 H+(aq) + O2(g) ⟶ 2 H2(g) + Br2(aq)Group of answer choicesreaction is spontaneous becuase voltage potential is negativereaction is not spontaneous becuase the voltage potential is positivereaction is spontaneous becuase voltage potential is positivereaction is not spontaneous becuase the voltage potential is negative

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Solution

To determine whether a reaction is spontaneous or not, we need to calculate the cell potential (E°cell). The cell potential is calculated using the half-reaction potentials of the oxidation and reduction reactions.

The half-reaction potentials are usually given, but in this case, they are not. However, we can look them up in a standard reduction potentials table.

The reaction 2 H+(aq) + O2(g) ⟶ 2 H2(g) + Br2(aq) can be split into two half-reactions:

  1. 2 H+(aq) + 2e- ⟶ H2(g) (Reduction half-reaction)
  2. Br2(aq) + 2e- ⟶ 2 Br-(aq) (Oxidation half-reaction)

Looking up the standard reduction potentials, we find:

E°(H2/H+) = 0.00 V E°(Br2/Br-) = 1.07 V

Since the reaction is written as a reduction, we need to reverse the sign for the oxidation half-reaction.

So, E°(Br-/Br2) = -1.07 V

The overall cell potential is the sum of the potentials of the half-reactions:

E°cell = E°cathode - E°anode E°cell = E°(H2/H+) - E°(Br-/Br2) E°cell = 0.00 V - (-1.07 V) E°cell = 1.07 V

Since the cell potential is positive, the reaction is spontaneous. Therefore, the correct answer is "reaction is spontaneous because the voltage potential is positive".

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