f the sum of the areas of two circles with radii R1 and R2 is eq

If the sum of the areas of two circles with radii R1 and R2 is equal to the area ofa circle of radius R, then(A) R1 + R 2 = R (B) 21R + 22R = R 2(C) R1 + R 2 < R (D) 2 2 21 2R R R

(i) Area enclosed by two concentric circles with radius R and r respectively such that R > r is π(R2 – r2).(ii) The length of tangents drawn from an external point to a circle are not equal.(iii) There is one and only one tangent at any point on the circumference of a circle.(iv) Ratio of the area of the sector of a circle with central angle 90° to the area of that circle is 1 : 4.A (i)-F, (ii)-F, (iii)-F, (iv)-F B (i)-F, (ii)-T, (iii)-F, (iv)-F C (i)-T, (ii)-F, (iii)-T, (iv)-T D (i)-T, (ii)-T, (iii)-T, (iv)-T

Two equal circles of radius r intersect such that each passes through the centre of the other. The length of common chord of the circles is

Two circles are placed in an equilateral triangle as shown in the figure. What is the ratio of the area of the smaller circle to that of the equilateral triangleπ:36√3π:18√3π:27√3π:42√3

The figure below shows a circle with center C and radius 6. What is the sum of the areas of the two shaded regions? Select one:a.4πb.3πc.4.5πd.7.5πe.6π