Knowee
Questions
Features
Study Tools

Two pith balls, each with a mass of 1.2 g, are attached to non-conducting threads and suspended from a common hook. Each thread has a length of 29.7 cm. The balls are then given an identical charge, which causes them to separate. In equilibrium, the threads are separated by an angle of 10.0°. Calculate the charge on each pith ball, in coulombs (C).

Question

Two pith balls, each with a mass of 1.2 g, are attached to non-conducting threads and suspended from a common hook. Each thread has a length of 29.7 cm. The balls are then given an identical charge, which causes them to separate. In equilibrium, the threads are separated by an angle of 10.0°. Calculate the charge on each pith ball, in coulombs (C).

🧐 Not the exact question you are looking for?Go ask a question

Solution

To solve this problem, we need to use Coulomb's Law and the formula for the tension in the strings.

Step 1: Identify the forces acting on the pith balls. There are two forces acting on each pith ball: the gravitational force (Fg) and the electrostatic force (Fe).

Step 2: Calculate the gravitational force. Fg = m*g where m is the mass of the pith ball (1.2 g = 0.0012 kg) and g is the acceleration due to gravity (9.8 m/s^2). Fg = 0.0012 kg * 9.8 m/s^2 = 0.01176 N

Step 3: Calculate the electrostatic force. The electrostatic force can be calculated using Coulomb's Law: Fe = kq1q2/r^2 where k is Coulomb's constant (8.9910^9 Nm^2/C^2), q1 and q2 are the charges on the pith balls (which are the same, so we can call this q), and r is the distance between the pith balls.

Step 4: Calculate the distance between the pith balls. The distance between the pith balls can be calculated using trigonometry. The pith balls and the point where the threads are attached form an isosceles triangle. The distance between the pith balls is the base of this triangle. We can calculate this distance using the formula: r = 2Lsin(θ/2) where L is the length of the thread (29.7 cm = 0.297 m) and θ is the angle between the threads (10.0°). r = 20.297 msin(10.0°/2) = 0.0518 m

Step 5: Set the gravitational force equal to the electrostatic force and solve for q. Fg = Fe 0.01176 N = (8.9910^9 Nm^2/C^2)q^2/(0.0518 m)^2 Solving this equation for q gives: q = sqrt((0.01176 N * (0.0518 m)^2) / (8.9910^9 Nm^2/C^2)) = 1.6110^-8 C

So, the charge on each pith ball is 1.61*10^-8 C.

This problem has been solved

Similar Questions

Two small conducting balls A and B of radius r1 and r2 have charges q1 and q2 respectively. They are connected by a wire.Obtain the expression for charges on A and B, in equilibrium

Two small balls having equal charges Q, are suspended from a hook with two insulating threads each of length L. This arrangement is carried in the space, where there is no gravitation. The tension in each string will be-

The sum of two point charges is 7μC. They repel each other with a force of 1N when kept 30cm apart in free space. Calculate the value of each charge.

If the specific charge (charge to mass ratio) of first ball is k, the specific charge of second ball isChoose answer: 2k 4k

Four identical metal objects carry the following charges: +17.52, ‒2.28, ‒9.77, and+19.34 C. The objects are brought simultaneously into contact, so that each touches theothers, and then they are separated.(i) Calculate the final charge on each object. [2 marks](ii) If one of the charges is then isolated from the others, determine the electric fieldstrength at a distance of 0.4 m from it, by making use of a 0.1 C test charge locatedat that point.

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.