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A student uses a machine to lift a 500N weight vertically a distance of 3 meters in 5 seconds. What is the power output, assuming that no other external factors are acting during the lift?

Question

A student uses a machine to lift a 500N weight vertically a distance of 3 meters in 5 seconds. What is the power output, assuming that no other external factors are acting during the lift?

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Solution

To calculate the power output, we first need to calculate the work done. Work done (W) is given by the formula:

W = Force (F) x Distance (d)

Given that the force (weight lifted) is 500N and the distance is 3m, we can substitute these values into the formula:

W = 500N x 3m = 1500 Joules

Power (P) is defined as the work done per unit time (t). So, we can calculate power using the formula:

P = W/t

Substituting the given values:

P = 1500J / 5s = 300 Watts

So, the power output of the machine is 300 Watts.

This problem has been solved

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