To find the smallest number of five digits that is exactly divisible by 476, we can start by finding the least common multiple (LCM) of 476 and 10,000.

Step 1: Prime factorize 476:
476 = 2^2 * 7 * 17

Step 2: Prime factorize 10,000:
10,000 = 2^4 * 5^4

Step 3: Find the LCM by taking the highest power of each prime factor:
LCM = 2^4 * 5^4 * 7 * 17

Step 4: Calculate the LCM:
LCM = 16 * 625 * 7 * 17 = 476,000

Therefore, the smallest number of five digits exactly divisible by 476 is 476,000.

Question

To find the smallest number of five digits that is exactly divisible by 476, we can start by finding the least common multiple (LCM) of 476 and 10,000.

Step 1: Prime factorize 476:
476 = 2^2 * 7 * 17

Step 2: Prime factorize 10,000:
10,000 = 2^4 * 5^4

Step 3: Find the LCM by taking the highest power of each prime factor:
LCM = 2^4 * 5^4 * 7 * 17

Step 4: Calculate the LCM:
LCM = 16 * 625 * 7 * 17 = 476,000

Therefore, the smallest number of five digits exactly divisible by 476 is 476,000.

Knowee AI · Accepted Answer

To find the smallest number of five digits that is exactly divisible by 476, we can start by finding the least common multiple (LCM) of 476 and 10,000.

Step 1: Prime factorize 476:
476 = 2^2 * 7 * 17

Step 2: Prime factorize 10,000:
10,000 = 2^4 * 5^4

Step 3: Find the LCM by taking the highest power of each prime factor:
LCM = 2^4 * 5^4 * 7 * 17

Step 4: Calculate the LCM:
LCM = 16 * 625 * 7 * 17 = 476,000

Therefore, the smallest number of five digits exactly divisible by 476 is 476,000.

The smallest number of five digits exactly divisible by 476 isOptions47600104761047210000

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