Write the oxidation and reduction half-reactions (without states of matter) for the following reaction:→+Cas  2Ag+aq + Ca2+aq  2Ags

The given reaction is: Ca + 2Ag+ → Ca2+ + 2Ag

The oxidation half-reaction is the process where a substance loses electrons. In this case, calcium (Ca) is losing two electrons to become Ca2+. So, the oxidation half-reaction is:

Ca → Ca2+ + 2e-

The reduction half-reaction is the process where a substance gains electrons. Here, silver ion (Ag+) is gaining one electron to become silver (Ag). Since there are two silver ions gaining one electron each, the reduction half-reaction is:

2Ag+ + 2e- → 2Ag

So, the oxidation half-reaction is Ca → Ca2+ + 2e-, and the reduction half-reaction is 2Ag+ + 2e- → 2Ag.