Walking with 6/7th of his usual speed , Prakash was late by 12 minutes . What is the usual time taken by Prakash to cover the distance ?1 hr 12 min1 hr2 hr1 hr 42 min2 hr 12 min

Let's solve this step by step:

Step 1: Let's assume the usual speed of Prakash is 's' km/hr and the usual time taken is 't' hours. So, the distance he covers would be speed * time = s*t km.

Step 2: According to the problem, Prakash is now walking with 6/7th of his usual speed. So, his new speed is 6/7*s km/hr.

Step 3: The distance he covers remains the same, so we can set up the equation for his new speed and time: (6/7)s * (t + 12/60) = st. Here, 12/60 is converting 12 minutes into hours.

Step 4: Simplify the equation: 6/7*t + 6/35 = t.

Step 5: Solve for 't': t = 1.4 hours, which is equivalent to 1 hour 24 minutes.

So, the usual time taken by Prakash to cover the distance is 1 hour 24 minutes.

Let's denote the usual speed of Prakash as 's' (in km/hr) and the usual time taken by him to cover the distance as 't' (in hours).

Step 1: According to the problem, Prakash walked with 6/7th of his usual speed. So, his speed on that day was 6/7 * s.

Step 2: Since speed is inversely proportional to time (when distance is constant), the time taken by him on that day was 7/6 * t.

Step 3: It is given that he was late by 12 minutes, which is 12/60 = 0.2 hours. So, 7/6 * t = t + 0.2.

Step 4: Solving the above equation, we get t = 1.2 hours, which is 1 hour 12 minutes.

So, the usual time taken by Prakash to cover the distance is 1 hour 12 minutes.

Let's solve this step by step:

Step 1: Let's assume the usual speed of Prakash is 's' km/hr and the usual time taken is 't' hours. So, the distance he covers would be speed * time = s*t km.

Step 2: Now, when Prakash walks with 6/7th of his usual speed, his speed becomes 6s/7 km/hr.

Step 3: The distance remains the same, so the time taken at this slower speed would be distance/speed = s*t / (6s/7) = 7t/6 hours.

Step 4: We know that this slower speed made him 12 minutes late. So, the difference between the slower time and the usual time is 12 minutes, which is 12/60 = 0.2 hours.

Step 5: Therefore, we can set up the equation 7t/6 = t + 0.2.

Step 6: Solving this equation, we get t = 1.2 hours, which is 1 hour and 12 minutes.

So, the usual time taken by Prakash to cover the distance is 1 hour and 12 minutes.

Let's denote the usual speed of Prakash as S (in km/hour or any other unit) and the usual time taken by him to cover the distance as T (in hours or any other unit).

According to the problem, when Prakash walks with 6/7th of his usual speed, he takes T + 12/60 hours to cover the same distance.

We know that speed = distance/time. Since the distance remains the same in both cases, we can write the following equation using the concept of relative speed:

S = (6/7)S * (T + 12/60)

Solving this equation for T gives us:

T = 1 hour 42 minutes

So, the usual time taken by Prakash to cover the distance is 1 hour 42 minutes.

Let's denote the usual speed of Prakash as S (in km/hour for example), and the usual time he takes to cover the distance as T (in hours).

Step 1: When Prakash walks with 6/7th of his usual speed, his speed becomes 6/7 * S.

Step 2: The time he takes to cover the same distance at this slower speed is the distance divided by the new speed. The distance is the usual speed times the usual time (ST), and the new speed is 6/7 * S. So, the new time is (ST) / (6/7 * S) = 7/6 * T.

Step 3: We know that this new time is his usual time plus 12 minutes, which is 12/60 = 0.2 hours. So, we have the equation 7/6 * T = T + 0.2.

Step 4: Solving this equation for T, we get T = 1.2 hours, which is 1 hour and 12 minutes.

So, the usual time taken by Prakash to cover the distance is 1 hour and 12 minutes.

Let's denote the usual speed of Prakash as S (in km/hour or any other unit) and the usual time taken by him as T (in hours or any other unit).

Step 1: According to the problem, Prakash walked with 6/7th of his usual speed. So, his speed during this particular journey was 6/7 * S.

Step 2: We know that speed = distance/time. Therefore, time = distance/speed. The time taken by Prakash for this particular journey was distance/(6/7 * S) = 7/6 * T.

Step 3: The problem states that Prakash was late by 12 minutes, which is 12/60 = 0.2 hours. Therefore, the usual time taken by him (T) plus the extra time (0.2 hours) equals the time taken for this particular journey: T + 0.2 = 7/6 * T.

Step 4: Solving the above equation for T, we get T = 1.2 hours, which is equivalent to 1 hour 12 minutes.

So, the usual time taken by Prakash to cover the distance is 1 hour 12 minutes.