Knowee
Questions
Features
Study Tools

Q6: Suppose your hair grows at the rate 1/32 in per day. What is the rate at which it grows in nanometers per second? [1 in = 2.54 cm, 1 d = 86 400 s, and 109 nm = 1 m] (a) 92.0 nm/s (b) 91.9 nm/s (c) 9.2 nm/s (d) 91.0 nm/s (e) 919.0 nm/s Q7: The JCR of a student hostel is 50.0 ft long and 26 ft wide and has 8.0-ft high ceilings. What is the volume of the interior of the room in cubic centimeters? [1 ft = 0.304 8 m]. (a) 2.94 × 103 cm3 (b) 3.17 × 103 cm3 (c) 2.94 × 108 cm3 (d) 2.9 × 108 cm3 (e) 2.98 × 108 cm3 4

Question

Q6: Suppose your hair grows at the rate 1/32 in per day. What is the rate at which it grows in nanometers per second? [1 in = 2.54 cm, 1 d = 86 400 s, and 109 nm = 1 m] (a) 92.0 nm/s (b) 91.9 nm/s (c) 9.2 nm/s (d) 91.0 nm/s (e) 919.0 nm/s Q7: The JCR of a student hostel is 50.0 ft long and 26 ft wide and has 8.0-ft high ceilings. What is the volume of the interior of the room in cubic centimeters? [1 ft = 0.304 8 m]. (a) 2.94 × 103 cm3 (b) 3.17 × 103 cm3 (c) 2.94 × 108 cm3 (d) 2.9 × 108 cm3 (e) 2.98 × 108 cm3 4

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

Sure, I can help with that. Let's solve these problems one by one.

Q6: First, we need to convert the rate from inches per day to nanometers per second.

1 inch/day = 1/32 inch/day = 0.03125 inch/day

Now, convert inches to centimeters:

0.03125 inch/day * 2.54 cm/inch = 0.079375 cm/day

Then, convert centimeters to meters:

0.079375 cm/day * 1 m/100 cm = 0.00079375 m/day

Next, convert meters to nanometers:

0.00079375 m/day * 10^9 nm/m = 793750000 nm/day

Finally, convert days to seconds:

793750000 nm/day * 1 day/86400 s = 919.0 nm/s

So, the answer is (e) 919.0 nm/s.

Q7: To find the volume of the room, we need to multiply its length, width, and height. But first, we need to convert the measurements from feet to centimeters.

Length = 50.0 ft * 0.3048 m/ft * 100 cm/m = 1524 cm Width = 26 ft * 0.3048 m/ft * 100 cm/m = 792.48 cm Height = 8.0 ft * 0.3048 m/ft * 100 cm/m = 243.84 cm

Volume = Length * Width * Height = 1524 cm * 792.48 cm * 243.84 cm = 2.94 × 10^8 cm^3

So, the answer is (c) 2.94 × 10^8 cm^3.

This problem has been solved

Similar Questions

10.  If a quantity increases with time, its related rates is negative.Group of answer choicesTrueFalse

A chemistry graduate student is studying the rate of this reaction:→ClCH2CH2Clg+CH2CHClgHClgShe fills a reaction vessel with ClCH2CH2Cl and measures its concentration as the reaction proceeds:time(seconds) ClCH2CH2Cl0 0.800M10. 0.359M20. 0.232M30. 0.171M40. 0.136MUse this data to answer the following questions.Write the rate law for this reaction. rate =k Calculate the value of the rate constant k.Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol. =k

A chemistry graduate student is studying the rate of this reaction:→2NH3g+N2g3H2gHe fills a reaction vessel with NH3 and measures its concentration as the reaction proceeds:time(seconds) NH30 0.0300M0.10 0.00957M0.20 0.00569M0.30 0.00405M0.40 0.00314MUse this data to answer the following questions.Write the rate law for this reaction. rate =k Calculate the value of the rate constant k.Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol. =k

Find the rate of growth after 4 hours. (Round your answer to the nearest whole number.)P'(4) = bacteria per hour

Two friends, Anita and Candice, are growing out their hair. They plan to cut it off at a certain point and donate it to a charity that makes wigs for people with cancer. Anita's hair is already 26 centimeters long and grows at a constant rate of 1 centimeter per month. Candice's hair is 16 centimeters and growing at a speed of 2 centimeters per month. If the girls get their hair cut on a certain day, they will have exactly the same length to donate. How long will their hair be? How long will that take?

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.