the opening batsman in the 9a s scored 156 runs total. If batsman 1 scored 7 times as many runs as batsman 2 and batsman 3 scored 15 less than batsman 1, determine the scores of the three batsman
Question
the opening batsman in the 9a s scored 156 runs total. If batsman 1 scored 7 times as many runs as batsman 2 and batsman 3 scored 15 less than batsman 1, determine the scores of the three batsman
Solution
Let's denote the score of batsman 2 as x.
According to the problem, batsman 1 scored 7 times as many runs as batsman 2. So, the score of batsman 1 is 7x.
Batsman 3 scored 15 less than batsman 1. So, the score of batsman 3 is 7x - 15.
The total score of the three batsmen is 156 runs. So, we can set up the following equation:
x (batsman 2's score) + 7x (batsman 1's score) + 7x - 15 (batsman 3's score) = 156
This simplifies to:
15x - 15 = 156
Adding 15 to both sides gives:
15x = 171
Dividing both sides by 15 gives:
x = 11.4
However, in cricket, a batsman cannot score a fraction of a run. Therefore, there seems to be a mistake in the problem as it does not result in a whole number for the score of batsman 2. Please check the problem and try again.
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