Assertion: Calcium carbonate on heating breaks down into calcium oxide and carbon dioxide gas.Reason: Calcium carbonate is a base
Question
Assertion: Calcium carbonate on heating breaks down into calcium oxide and carbon dioxide gas.Reason: Calcium carbonate is a base
Solution
The assertion and reason given are related but the reason is not the correct explanation for the assertion.
Assertion: Calcium carbonate on heating breaks down into calcium oxide and carbon dioxide gas. This is a correct statement. When calcium carbonate is heated, it undergoes a chemical reaction known as thermal decomposition to form calcium oxide and carbon dioxide. The reaction can be represented as follows:
CaCO3(s) → CaO(s) + CO2(g)
Reason: Calcium carbonate is a base. This is also a correct statement. Calcium carbonate is a base because it reacts with acids to form a salt and water. However, this property is not the reason why calcium carbonate decomposes into calcium oxide and carbon dioxide upon heating. The decomposition of calcium carbonate upon heating is due to the instability of the compound at high temperatures, not because it is a base.
Similar Questions
For the following question two statements are given – one labelled Assertion (A) and the other labelled Reason (R).Assertion: Calcium carbonate on heating breaks down into calcium oxide and carbon dioxide gas.Reason: Calcium carbonate is a base.Select the correct answer to the question.
Calcium carbonate decomposes on heating. The word equation for this reaction is
Calcium carbonate (CaCO3) is a common substance found in rocks. When it's heated, it breaks down to form a new solid, calcium oxide (CaO). This reaction releases carbon dioxide gas (CO2).Write a symbol equation for this reaction, including state symbols.Note: You can copy and paste this arrow: →
Consider the decomposition of calcium carbonate shown below. Which of the following statements correctly describes this reaction as it occurs in a test tube? CaCO3(s) + 42.5 kcal → CaO(s) + CO2(g)It is impossible to predict without actually performing the experiment.The test tube would feel warm, since the reaction would release heat to the surroundings.The test tube would feel cold, since the reaction would absorb heat from the surroundings.The test tube would feel warm, since the reaction would absorb heat from the surroundings.The test tube would feel cold, since the reaction would release heat to the surroundings.
Calcium carbonate decomposes at high temperature to form carbon dioxide and calcium oxide:CaCO3 ⟶ CO2 + CaOHow many grams of calcium carbonate are needed to form 93.02 L of carbon dioxide at STP?
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