Three resistors are connected in series to each other with a total resistance of 7.25Ω. What is the resistance of the 3rd resistor if R1 and R2 has the same individual resistance of 2.5Ω?
Question
Three resistors are connected in series to each other with a total resistance of 7.25Ω. What is the resistance of the 3rd resistor if R1 and R2 has the same individual resistance of 2.5Ω?
Solution
To find the resistance of the third resistor, you need to subtract the total resistance of the first two resistors from the total resistance of the circuit.
Here are the steps:
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Find the total resistance of the first two resistors. Since R1 and R2 have the same resistance of 2.5Ω, you can add them together.
R1 + R2 = 2.5Ω + 2.5Ω = 5Ω
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Subtract the total resistance of the first two resistors from the total resistance of the circuit to find the resistance of the third resistor.
R3 = Total resistance - (R1 + R2) = 7.25Ω - 5Ω = 2.25Ω
So, the resistance of the third resistor is 2.25Ω.
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