(2v–1)(v+2)Submit

To solve the expression "(2v–1)(v+2)", you need to apply the distributive property, also known as the FOIL method. Here's how you do it:

Step 1: Multiply the first terms in each binomial: 2v * v = 2v^2

Step 2: Multiply the outer terms in the expression: 2v * 2 = 4v

Step 3: Multiply the inner terms in the expression: -1 * v = -v

Step 4: Multiply the last terms in each binomial: -1 * 2 = -2

Step 5: Add all the results together: 2v^2 + 4v - v - 2

Step 6: Combine like terms: 2v^2 + 3v - 2

So, (2v–1)(v+2) = 2v^2 + 3v - 2.