A voltage of 240 V is applied to a circuit of 800 Ω in series with 1600 Ω. The voltage across the 1600 Ω resistor is measured with a voltmeter having full scale deflection of 250 V and sensitivity of 100 Ω/V. What voltage does the meter indicate?

To solve this problem, we need to follow these steps:

1. First, we need to find the total resistance in the circuit. Since the resistors are in series, we simply add the resistances together. So, the total resistance (Rt) is 800 Ω + 1600 Ω = 2400 Ω.

2. Next, we use Ohm's Law (V = I*R) to find the total current (It) in the circuit. We rearrange the formula to solve for current: I = V/R. So, the total current is 240 V / 2400 Ω = 0.1 A.

3. Now, we can find the voltage across the 1600 Ω resistor (Vr). Again, we use Ohm's Law, but this time we know the current and the resistance, so we solve for voltage: V = I*R. So, the voltage across the 1600 Ω resistor is 0.1 A * 1600 Ω = 160 V.

4. Finally, we need to consider the voltmeter's full scale deflection and sensitivity. The voltmeter's resistance (Rm) can be calculated by multiplying its full scale deflection by its sensitivity: Rm = 250 V * 100 Ω/V = 25000 Ω.

5. The voltmeter and the 1600 Ω resistor form a voltage divider. The voltage across the voltmeter (Vm) can be calculated using the voltage divider rule: Vm = Vr * Rm / (Rm + 1600 Ω). So, the voltage that the meter indicates is 160 V * 25000 Ω / (25000 Ω + 1600 Ω) = 147.9 V.

So, the voltmeter will indicate a voltage of approximately 147.9 V.