Sure, here is the step by step solution:

1. A regular deck of playing cards has 52 cards in total, with 4 of them being kings.

2. The probability of drawing a king on the first draw is 4 out of 52 (since there are 4 kings in a deck of 52 cards). This can be simplified to 1/13.

3. If we do not replace the first card (which is a king), there are now 51 cards left in the deck, with 3 of them being kings.

4. The probability of drawing a king on the second draw is therefore 3 out of 51. This can be simplified to approximately 1/17.

5. The probability of both events happening (drawing a king on the first draw AND drawing a king on the second draw) is the product of the probabilities of each event.

6. Therefore, the probability that both cards drawn are kings (without replacement) is (1/13) * (1/17) = 1/221, or approximately 0.00452 when rounded to five decimal places.

Question

Sure, here is the step by step solution:

1. A regular deck of playing cards has 52 cards in total, with 4 of them being kings.

2. The probability of drawing a king on the first draw is 4 out of 52 (since there are 4 kings in a deck of 52 cards). This can be simplified to 1/13.

3. If we do not replace the first card (which is a king), there are now 51 cards left in the deck, with 3 of them being kings.

4. The probability of drawing a king on the second draw is therefore 3 out of 51. This can be simplified to approximately 1/17.

5. The probability of both events happening (drawing a king on the first draw AND drawing a king on the second draw) is the product of the probabilities of each event.

6. Therefore, the probability that both cards drawn are kings (without replacement) is (1/13) * (1/17) = 1/221, or approximately 0.00452 when rounded to five decimal places.

Knowee AI · Accepted Answer

Sure, here is the step by step solution:

1. A regular deck of playing cards has 52 cards in total, with 4 of them being kings.

2. The probability of drawing a king on the first draw is 4 out of 52 (since there are 4 kings in a deck of 52 cards). This can be simplified to 1/13.

3. If we do not replace the first card (which is a king), there are now 51 cards left in the deck, with 3 of them being kings.

4. The probability of drawing a king on the second draw is therefore 3 out of 51. This can be simplified to approximately 1/17.

5. The probability of both events happening (drawing a king on the first draw AND drawing a king on the second draw) is the product of the probabilities of each event.

6. Therefore, the probability that both cards drawn are kings (without replacement) is (1/13) * (1/17) = 1/221, or approximately 0.00452 when rounded to five decimal places.

From a pack of regular playing cards, two cards are drawn at random. What is the probability that both cards will be kings, if the card is NOT replaced?

Question

Solution

Similar Questions

Upgrade your grade with Knowee