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You are hosting a potluck.  Five people are bringing drinks (5 different drinks), 4 people are bringing main courses (4 different main courses), and 3 people are bringing desserts (3 different desserts).  How many different possible assemblies of drink/main course/dessert could be put together?20601224

Question

You are hosting a potluck.  Five people are bringing drinks (5 different drinks), 4 people are bringing main courses (4 different main courses), and 3 people are bringing desserts (3 different desserts).  How many different possible assemblies of drink/main course/dessert could be put together?20601224

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Solution

The question is asking for the total number of different possible combinations of drink, main course, and dessert that could be put together. This is a problem of combinations in probability theory.

The number of combinations is calculated by multiplying the number of options in each category together. In this case, we have:

  • 5 options for drinks
  • 4 options for main courses
  • 3 options for desserts

So, the total number of combinations is 5 (drinks) * 4 (main courses) * 3 (desserts) = 60 different possible assemblies of drink/main course/dessert.

This problem has been solved

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