Factor completely.4, x, squared, minus, 4, x, minus, 34x 2 −4x−3

It seems like there might be a typo in your question. If you're asking to factor the quadratic equation 4x^2 - 4x - 3, here are the steps:

1. First, identify the coefficients a, b, and c in the quadratic equation ax^2 + bx + c. In this case, a = 4, b = -4, and c = -3.

2. Next, find two numbers that multiply to a*c (which is -12 in this case) and add up to b (which is -4 in this case). The numbers that satisfy these conditions are -6 and 2.

3. Rewrite the middle term of the quadratic equation as the sum of the terms -6x and 2x. This gives us 4x^2 - 6x + 2x - 3.

4. Factor by grouping. The first two terms can be factored as 2x(2x - 3), and the last two terms can be factored as 1(2x - 3).

5. Since the terms in parentheses are the same, we can factor them out to get (2x - 3)(2x + 1).

So, the factored form of the equation 4x^2 - 4x - 3 is (2x - 3)(2x + 1).

The expression you provided seems to have a typo. If the expression is 4x^2 - 4x - 3, then here's how to factor it:

Step 1: Identify the coefficients of the quadratic equation. Here, a = 4, b = -4, and c = -3.

Step 2: Find two numbers that multiply to (a*c) = -12 and add to b = -4. The numbers are -6 and 2.

Step 3: Rewrite the middle term of the quadratic equation as the sum of the terms -6x and 2x. This gives us 4x^2 - 6x + 2x - 3.

Step 4: Factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together. This gives us 2x(2x - 3) + 1(2x - 3).

Step 5: Notice that (2x - 3) is a common factor. Factor out this term to get the final factored form of the equation: (2x - 3)(2x + 1).

So, 4x^2 - 4x - 3 factors to (2x - 3)(2x + 1).