The equation of the line fitted to the timed and untimed average ratings of trustworthiness is timed_ave_rating = 1.554 + 0.5134 * untimed_ave_ratingAn individual photo that has a timed average trustworthiness rating of 5.8 and an untimed average trustworthiness rating of 5.1 would have a predicted timed average trustworthiness rating of and a residual/prediction error of (round your answer to 1 decimal place)
Question
The equation of the line fitted to the timed and untimed average ratings of trustworthiness is timed_ave_rating = 1.554 + 0.5134 * untimed_ave_ratingAn individual photo that has a timed average trustworthiness rating of 5.8 and an untimed average trustworthiness rating of 5.1 would have a predicted timed average trustworthiness rating of and a residual/prediction error of (round your answer to 1 decimal place)
Solution
To calculate the predicted timed average trustworthiness rating, we can substitute the untimed average trustworthiness rating into the equation:
timed_ave_rating = 1.554 + 0.5134 * untimed_ave_rating
Substituting untimed_ave_rating = 5.1, we get:
timed_ave_rating = 1.554 + 0.5134 * 5.1 = 4.2 (rounded to 1 decimal place)
The residual or prediction error is the difference between the observed and predicted values. In this case, it is:
residual = observed - predicted = 5.8 - 4.2 = 1.6 (rounded to 1 decimal place)
So, the predicted timed average trustworthiness rating is 4.2 and the residual/prediction error is 1.6.
Similar Questions
After viewing the image, participants were asked to rate the person's trustworthiness on a scale of 0 to 100 points. The researchers conducted a two sample t-test, using the following hypotheses: • Ho: The underlying mean trustworthiness rating for the happy face is the same as the underlying mean trustworthiness rating for the more neutral face • Hy: The underlying mean trustworthiness rating for the happy face is not the same as the underling mean trustworthiness rating for the more neutral face The researchers found a difference of 1.3 points between the mean trustworthiness rating for each group (p-value = 0.0243), with the group that were shown an image of an Al- generated person with a happy face having the higher mean. The observed difference of 1.3 points is ? or is not statistically significant at 10% level?
The equation of the line fitted is Metascore = -20.9 + 12.5 * imdbRating Using a linear model based on this fitted line: A group of movies that all have an imdbRating of 7.2 is estimated to have a mean Metascore of ______ (round your answer to one decimal place e.g. 32.0 or 64.1). An individual movie that has an imdbRating of 7.2 and an actual Metascore of 63.7 would have a residual/prediction error of ________ (round your answer to one decimal place e.g. 32.0 or -64.1). A prediction model was developed to generate prediction intervals for Metascore, using the line fitted and a fixed error amount of 2 x RMSE. The RMSE for this sample data is 13.3. Using this prediction model, the Metascore for a movie with an imdbRating of 7.2 is predicted to be between and (round your interval limits to one decimal place).
The 99% confidence interval to estimate the mean number of hours per week people watch Netflix is (20.5, 24.3). What value must be in the interval?
Which among the following is NOT a criteria used by a trustor to determine perceived trustworthiness?ResponsesDiversityDiversityBenevolenceBenevolenceAbilityAbilityIntegrity
The formula in the image is a coefficient of reliability known as Cronbach's _____.Answer instructionsOmegaCommaGammaThetaAlpha
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.