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In a communication system each data packet consists of 10001000 bits. Due to the noise, each bit may be received in error with probability 0.10.1. It is assumed bit errors occur independently. Find the probability that there are more than 120120 errors in a certain data packet.

Question

In a communication system each data packet consists of 10001000 bits. Due to the noise, each bit may be received in error with probability 0.10.1. It is assumed bit errors occur independently. Find the probability that there are more than 120120 errors in a certain data packet.

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Solution

To find the probability that there are more than 120 errors in a certain data packet, we can use the binomial distribution.

The binomial distribution is used when there are two possible outcomes (in this case, a bit being received correctly or in error) and each outcome has a fixed probability (in this case, the probability of a bit being received in error is 0.1).

Let's denote the number of errors in a data packet as X. We want to find P(X > 120).

To calculate this probability, we need to sum up the probabilities of all possible values of X greater than 120. However, calculating this directly can be quite cumbersome.

Instead, we can use the complement rule. The complement of the event "X > 120" is "X <= 120". So, we can find the probability of "X <= 120" and subtract it from 1 to get the probability of "X > 120".

The probability of "X <= 120" can be calculated using the cumulative distribution function (CDF) of the binomial distribution. The CDF gives the probability of getting up to a certain number of successes (in this case, errors) in a fixed number of trials (in this case, the number of bits in a data packet).

Using a binomial distribution calculator or software, we can find P(X <= 120) to be approximately 0.999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

This problem has been solved

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