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Scanner input = new Scanner("This\nhas 5\n4\nlines\n");System.out.println("%" + input.next() + "%"); System.out.println("%" + input.nextLine() + "%"); System.out.println("%" + input.nextLine() + "%"); System.out.println("%" + input.nextInt() + "%"); System.out.println("%" + input.nextLine() + "%"); System.out.println("%" + input.nextLine() + "%");

Question

Scanner input = new Scanner("This\nhas 5\n4\nlines\n");System.out.println("%" + input.next() + "%"); System.out.println("%" + input.nextLine() + "%"); System.out.println("%" + input.nextLine() + "%"); System.out.println("%" + input.nextInt() + "%"); System.out.println("%" + input.nextLine() + "%"); System.out.println("%" + input.nextLine() + "%");

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Solution

The code you've provided is written in Java. It uses the Scanner class to read input from a string, and then prints out the results. Here's a step-by-step explanation of what the code does:

  1. Scanner input = new Scanner("This\nhas 5\n4\nlines\n"); This line creates a new Scanner object that will read from the provided string. The string contains four lines of text: "This", "has 5", "4", and "lines".

  2. System.out.println("%" + input.next() + "%"); This line prints out the next token from the scanner, surrounded by percentage signs. The next() method of the Scanner class reads until it encounters whitespace, so it will only read the word "This".

  3. System.out.println("%" + input.nextLine() + "%"); This line prints out the rest of the current line, again surrounded by percentage signs. Since the previous call to next() consumed the word "This" but not the newline character, nextLine() will return an empty string.

  4. System.out.println("%" + input.nextLine() + "%"); This line prints out the next line of the string, which is "has 5".

  5. System.out.println("%" + input.nextInt() + "%"); This line attempts to read the next token as an integer. The next line of the string is "4", which can be successfully parsed as an integer.

  6. System.out.println("%" + input.nextLine() + "%"); This line prints out the rest of the current line. Since the previous call to nextInt() consumed the number 4 but not the newline character, nextLine() will return an empty string.

  7. System.out.println("%" + input.nextLine() + "%"); Finally, this line prints out the last line of the string, which is "lines".

So, the output of this code would be:

%This%
%%
%has 5%
%4%
%%
%lines%

This problem has been solved

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