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A man draws 3 balls from a jug containing 5 white balls and 7 black balls. He gets Rs. 20 for each white ball and Rs. 10 for each black ball. What is his expectation?Rs. 21.25Rs. 42.50Rs. 31.25Rs, 45.21

Question

A man draws 3 balls from a jug containing 5 white balls and 7 black balls. He gets Rs. 20 for each white ball and Rs. 10 for each black ball. What is his expectation?Rs. 21.25Rs. 42.50Rs. 31.25Rs, 45.21

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Solution

The expectation or expected value in a probability problem is calculated by multiplying each possible outcome by the probability of that outcome, then adding those values.

First, we need to calculate the probability of drawing a white ball and a black ball.

The total number of balls is 5 (white) + 7 (black) = 12 balls.

The probability of drawing a white ball is 5/12 and for a black ball is 7/12.

The expected gain for a white ball is the product of the gain and the probability, which is Rs. 20 * 5/12 = Rs. 8.33.

Similarly, the expected gain for a black ball is Rs. 10 * 7/12 = Rs. 5.83.

The total expectation is the sum of these two expectations, which is Rs. 8.33 + Rs. 5.83 = Rs. 14.16.

So, the man can expect to gain Rs. 14.16 for each ball he draws. Since he draws 3 balls, his total expected gain is Rs. 14.16 * 3 = Rs. 42.48.

The closest answer to this is Rs. 42.50.

This problem has been solved

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