Consider the following SQL query: SELECT name FROM Customers WHERE date_registered > (SELECT MIN(date_registered) FROM Customers);OptionsThe names of customers who registered after the first registered customer. The names of customers who registered on the same date as the first registered customer.An error because the subquery returns multiple values.An error because the subquery is missing the FROM clause.

he following query throws an error. Choose the correct reason for the error as given in the options. SELECT first_name, last_nameFROM employeesWHERE commission_pct = (SELECT min(commission_pct ) FROM employees GROUP BY department_id); A. The GROUP BY clause is not required in the sub-queryB. A function cannot be used in a sub-query SELECT statementC. The single row sub-query gives multiple records

How do you retrieve the youngest employee's name and age? *SELECT Name, Age FROM Employees ORDER BY Age ASC LIMIT 1;SELECT MIN(Age), Name FROM Employees;SELECT LAST(Name), Age FROM Employees ORDER BY Age DESC;SELECT Name, Age FROM Employees WHERE Age = MIN(Age);

Which Sql Statement Retrieves The First 5 Distinct Customer Names From A Table Named Customers?

Evaluate this SQL statement:SELECT first_name, commissionFROM employeeWHERE commission =(SELECT commissionFROM employeeWHERE UPPER(first_name) = 'SCOTT');What would cause this statement to fail?Select one:a.All the given optionsb.The FIRST_NAME values in the database are in lowercase.c.There is more than one employee with the first name Scott.d.Scott has a zero commission value.e.Scalar function is not allowed in Subquery.

SELECT MIN(HIRE_DATE) FROM FACULTY