Sure, here is a Python program that will print the pattern as per your requirement:

```python
def print_pattern(n):
count = 1
for i in range(1, n+1):
temp = i
for j in range(i):
print(temp, end=' ')
temp += n - j
print()
count += 1

# Test Case 1
print("Enter the number of rows: 7")
print_pattern(7)

# Test Case 2
print("Enter the number of rows: 5")
print_pattern(5)
```

In this program, we define a function `print_pattern(n)` that takes an integer `n` as input and prints the desired pattern. The outer loop runs `n` times, and the inner loop runs `i` times where `i` is the current iteration of the outer loop. The variable `temp` is used to print the numbers in the pattern. It starts with the value of `i` and is incremented by `n - j` in each iteration of the inner loop, where `j` is the current iteration of the inner loop. The `end=' '` argument in the `print` function is used to print a space after each number instead of a newline. The `print()` statement after the inner loop is used to print a newline after each row of the pattern.

Question

Sure, here is a Python program that will print the pattern as per your requirement:

```python
def print_pattern(n):
    count = 1
    for i in range(1, n+1):
        temp = i
        for j in range(i):
            print(temp, end=' ')
            temp += n - j
        print()
        count += 1

# Test Case 1
print("Enter the number of rows: 7")
print_pattern(7)

# Test Case 2
print("Enter the number of rows: 5")
print_pattern(5)
```

In this program, we define a function `print_pattern(n)` that takes an integer `n` as input and prints the desired pattern. The outer loop runs `n` times, and the inner loop runs `i` times where `i` is the current iteration of the outer loop. The variable `temp` is used to print the numbers in the pattern. It starts with the value of `i` and is incremented by `n - j` in each iteration of the inner loop, where `j` is the current iteration of the inner loop. The `end=' '` argument in the `print` function is used to print a space after each number instead of a newline. The `print()` statement after the inner loop is used to print a newline after each row of the pattern.

Knowee AI · Accepted Answer

Sure, here is a Python program that will print the pattern as per your requirement:

```python
def print_pattern(n):
    count = 1
    for i in range(1, n+1):
        temp = i
        for j in range(i):
            print(temp, end=' ')
            temp += n - j
        print()
        count += 1

# Test Case 1
print("Enter the number of rows: 7")
print_pattern(7)

# Test Case 2
print("Enter the number of rows: 5")
print_pattern(5)
```

In this program, we define a function `print_pattern(n)` that takes an integer `n` as input and prints the desired pattern. The outer loop runs `n` times, and the inner loop runs `i` times where `i` is the current iteration of the outer loop. The variable `temp` is used to print the numbers in the pattern. It starts with the value of `i` and is incremented by `n - j` in each iteration of the inner loop, where `j` is the current iteration of the inner loop. The `end=' '` argument in the `print` function is used to print a space after each number instead of a newline. The `print()` statement after the inner loop is used to print a newline after each row of the pattern.

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