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A 0.480 kg wooden block is spun around on a wooden table. The wooden block is being spun around on a 2.00 m long massless wire. The wooden block has air being pushed out behind it causing a thrust force of 3.10 N. The air is being pushed out at 70.0° from the radial line as shown in the figure. If the block is initially at rest and the coefficient of friction is 0.300, what is the tension in the wire after 15.0 revolutions?

Question

A 0.480 kg wooden block is spun around on a wooden table. The wooden block is being spun around on a 2.00 m long massless wire. The wooden block has air being pushed out behind it causing a thrust force of 3.10 N. The air is being pushed out at 70.0° from the radial line as shown in the figure. If the block is initially at rest and the coefficient of friction is 0.300, what is the tension in the wire after 15.0 revolutions?

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Solution

This problem involves several steps and concepts from physics, including forces, friction, and circular motion. Here's how you can solve it:

Step 1: Identify the forces acting on the block. There are three forces acting on the block: the thrust force (F_thrust), the frictional force (F_friction), and the tension in the wire (T).

Step 2: Resolve the thrust force into radial and tangential components. The radial component (F_radial) is the component of the thrust force that acts along the radius of the circle, and the tangential component (F_tangential) is the component that acts tangent to the circle. They can be calculated using trigonometry:

F_radial = F_thrust * cos(70.0°) = 3.10 N * cos(70.0°) = 1.06 N F_tangential = F_thrust * sin(70.0°) = 3.10 N * sin(70.0°) = 2.92 N

Step 3: Calculate the frictional force. The frictional force can be calculated using the formula F_friction = μ * m * g, where μ is the coefficient of friction, m is the mass of the block, and g is the acceleration due to gravity (9.8 m/s²):

F_friction = 0.300 * 0.480 kg * 9.8 m/s² = 1.41 N

Step 4: Calculate the net force acting on the block. The net force (F_net) is the sum of the tangential component of the thrust force and the frictional force:

F_net = F_tangential - F_friction = 2.92 N - 1.41 N = 1.51 N

Step 5: Calculate the angular acceleration of the block. The angular acceleration (α) can be calculated using the formula F_net = m * r * α, where r is the radius of the circle:

α = F_net / (m * r) = 1.51 N / (0.480 kg * 2.00 m) = 1.57 rad/s²

Step 6: Calculate the angular displacement of the block. The angular displacement (θ) is the total angle through which the block has rotated. Since the block has completed 15.0 revolutions, θ = 15.0 * 2π rad = 94.2 rad.

Step 7: Calculate the final angular velocity of the block. The final angular velocity (ω_f) can be calculated using the formula ω_f² = ω_i² + 2αθ, where ω_i is the initial angular velocity. Since the block was initially at rest, ω_i = 0, so:

ω_f = sqrt(2 * α * θ) = sqrt(2 * 1.57 rad/s² * 94.2 rad) = 34.3 rad/s

Step 8: Calculate the tension in the wire. The tension in the wire can be calculated using the formula T = m * r * ω_f² + F_radial:

T = 0.480 kg * 2.00 m * (34.3 rad/s)² + 1.06 N = 1120 N

So, the tension in the wire after 15.0 revolutions is 1120 N.

This problem has been solved

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