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Select the correct answerWhat will be the output of the following Java program? class static_out { static int x; static int y; void add(int a , int b) { x = a + b; y = x + b; } } class static_use { public static void main(String args[]) { static_out obj1 = new static_out(); static_out obj2 = new static_out(); int a = 2; obj1.add(a, a + 1); obj2.add(5, a); System.out.println(obj1.x + " " + obj2.y); } }Options7 9 6 67 79 7

Question

Select the correct answerWhat will be the output of the following Java program? class static_out { static int x; static int y; void add(int a , int b) { x = a + b; y = x + b; } } class static_use { public static void main(String args[]) { static_out obj1 = new static_out(); static_out obj2 = new static_out(); int a = 2; obj1.add(a, a + 1); obj2.add(5, a); System.out.println(obj1.x + " " + obj2.y); } }Options7 9 6 67 79 7

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Solution

The correct answer is 7 7.

Here's the step by step explanation:

  1. In the main method, two objects of the class static_out are created, obj1 and obj2.
  2. The variable 'a' is initialized with the value 2.
  3. The add method is called on obj1 with parameters a and a+1 (which is 2 and 3). This sets x to 5 (2+3) and y to 8 (5+3).
  4. The add method is then called on obj2 with parameters 5 and a (which is 5 and 2). This sets x to 7 (5+2) and y to 7 (7+2-2, because x is now 7).
  5. The println statement prints the values of x and y. Since x and y are static variables, they are shared among all objects of the class. So, the values that are printed are the ones that were last set, which are 7 (from obj2.add) and 7 (from obj2.add).
  6. Therefore, the output of the program is "7 7".

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