People from a group are asked to form a circle for an activity. Then this group has to be split into two halves so that each group does a different activity as part of the original one. The task is to split it into two halves with exact same count or if there odd number of people, the first half can have more people than the other.Consider the arrangement to be in the form of a circular linked list and split it accordingly.
Question
People from a group are asked to form a circle for an activity. Then this group has to be split into two halves so that each group does a different activity as part of the original one. The task is to split it into two halves with exact same count or if there odd number of people, the first half can have more people than the other.Consider the arrangement to be in the form of a circular linked list and split it accordingly.
Solution 1
To split the group into two halves with an equal count or with the first half having more people if there is an odd number, we can follow these steps:
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Start by arranging the people in a circle, forming a circular linked list.
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Choose any person in the circle as the starting point.
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Traverse the circular linked list, counting the number of people in the group. Keep track of the total count.
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If the total count is even, divide it by 2 to determine the desired count for each half. If the total count is odd, divide it by 2 and round up to the nearest whole number to determine the desired count for the first half. The remaining count will be the desired count for the second half.
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Traverse the circular linked list again, starting from the chosen starting point. Stop at the desired count for the first half.
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Cut the circular linked list at this point, separating the first half from the second half.
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Connect the last person in the first half to the chosen starting point, completing the circular linked list for the first half.
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Connect the last person in the second half to the first person in the first half, completing the circular linked list for the second half.
Now, the group has been split into two halves with an equal count or with the first half having more people if there is an odd number. Each half can now proceed to do a different activity as part of the original one.
Solution 2
To split the group into two halves with an equal count or with the first half having more people if there is an odd number, we can follow these steps:
-
Start by arranging the people in a circle, forming a circular linked list.
-
Choose any person in the circle as the starting point.
-
Traverse the circular linked list, counting the number of people in the group. Keep track of the total count.
-
If the total count is even, divide it by 2 to determine the desired count for each half. If the total count is odd, divide it by 2 and round up to the nearest whole number to determine the desired count for the first half. The remaining count will be the desired count for the second half.
-
Traverse the circular linked list again, starting from the chosen starting point. Stop at the desired count for the first half.
-
Cut the circular linked list at this point, separating the first half from the second half.
-
Connect the last person in the first half to the chosen starting point, completing the circular linked list for the first half.
-
Connect the last person in the second half to the first person in the first half, completing the circular linked list for the second half.
Now, the group has been split into two halves with an equal count or with the first half having more people if there is an odd number. Each half can now proceed to do a different activity as part of the original one.
Similar Questions
So the number of ways N people can be arranged in a straight line if 2 particular people must be separated
There are n people that are split into some unknown number of groups. Each person is labeled with a unique ID from 0 to n - 1.You are given an integer array groupSizes, where groupSizes[i] is the size of the group that person i is in. For example, if groupSizes[1] = 3, then person 1 must be in a group of size 3.Return a list of groups such that each person i is in a group of size groupSizes[i].Each person should appear in exactly one group, and every person must be in a group. If there are multiple answers, return any of them. It is guaranteed that there will be at least one valid solution for the given input. Example 1:Input: groupSizes = [3,3,3,3,3,1,3]Output: [[5],[0,1,2],[3,4,6]]Explanation: The first group is [5]. The size is 1, and groupSizes[5] = 1.The second group is [0,1,2]. The size is 3, and groupSizes[0] = groupSizes[1] = groupSizes[2] = 3.The third group is [3,4,6]. The size is 3, and groupSizes[3] = groupSizes[4] = groupSizes[6] = 3.Other possible solutions are [[2,1,6],[5],[0,4,3]] and [[5],[0,6,2],[4,3,1]].Example 2:Input: groupSizes = [2,1,3,3,3,2]Output: [[1],[0,5],[2,3,4]]
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