Select the correct answerA person covers a certain distance with certain speed if he increases his speed by 15 km/hr. Then he will be 16 min. early. By how much time he will be late if he reduces his speed by 12 km/hr, if his initial speed is 60 km/hr?Options20 min15 min25 min24 min

To solve this problem, we need to understand the relationship between speed, distance, and time. The formula is Distance = Speed x Time.

1. First, let's find the distance using the initial speed and time. We know that if the person increases his speed by 15 km/hr, he arrives 16 minutes early. This means the time taken at the increased speed is the original time minus 16 minutes.

   But we don't know the original time yet, so let's denote it as T (in hours). The increased speed is 60 km/hr + 15 km/hr = 75 km/hr. So, the distance is 75 km/hr x (T - 16/60) hours.

2. This distance is the same as the one covered with the original speed, 60 km/hr. So, we also have Distance = 60 km/hr x T hours.

3. Now we can set these two equations equal to each other and solve for T:

   75(T - 16/60) = 60T 75T - 20 = 60T 15T = 20 T = 20/15 = 1.33 hours or 80 minutes.

4. Now, let's find out how late the person will be if he reduces his speed by 12 km/hr. The reduced speed is 60 km/hr - 12 km/hr = 48 km/hr.

5. Using the formula Distance = Speed x Time, the new time taken (let's denote it as T') is Distance / Speed = (60T) / 48 = 1.67 hours or 100 minutes.

6. So, the person will be late by T' - T = 100 minutes - 80 minutes = 20 minutes.

Therefore, the correct answer is 20 minutes.