The output of the given Python code will be `[[7], [7], [7], [7]]`.

Here's the step by step explanation:

1. `x=[[]]*4` creates a list of 4 empty lists. However, it's important to note that all 4 of these lists actually point to the same memory location. In other words, they are all the same list in memory.

2. `x[1].append(7)` appends the integer 7 to the second list in `x`. However, since all 4 lists are the same in memory, this actually appends 7 to all of the lists.

3. `print(x)` prints the list `x`, which is now a list of 4 lists, each containing the integer 7.

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The output of the given Python code will be `[[7], [7], [7], [7]]`.

Here's the step by step explanation:

1. `x=[[]]*4` creates a list of 4 empty lists. However, it's important to note that all 4 of these lists actually point to the same memory location. In other words, they are all the same list in memory.

2. `x[1].append(7)` appends the integer 7 to the second list in `x`. However, since all 4 lists are the same in memory, this actually appends 7 to all of the lists.

3. `print(x)` prints the list `x`, which is now a list of 4 lists, each containing the integer 7.

Knowee AI · Accepted Answer

The output of the given Python code will be `[[7], [7], [7], [7]]`.

Here's the step by step explanation:

1. `x=[[]]*4` creates a list of 4 empty lists. However, it's important to note that all 4 of these lists actually point to the same memory location. In other words, they are all the same list in memory.

2. `x[1].append(7)` appends the integer 7 to the second list in `x`. However, since all 4 lists are the same in memory, this actually appends 7 to all of the lists.

3. `print(x)` prints the list `x`, which is now a list of 4 lists, each containing the integer 7.

What will be the output of the following Python code?x=[[]]*4x[1].append(7)print(x)

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