wo point charges q1 = +5 x 10-19 and q2 = +20 x 10-19 are separated by a distance of 2m. Find the point on the line joining the at which electric llald intensity is zer

It seems like your question got cut off. However, I can help you find the point on the line joining two point charges where the electric field intensity is zero.

The electric field E created by a point charge q at a distance r is given by Coulomb's law:

E = k*q/r^2

where k is Coulomb's constant (9 x 10^9 N m^2/C^2).

The electric field is a vector quantity, so when two charges create electric fields at a point, the fields add up as vectors. The electric field is zero at a point if the fields created by the charges at that point are equal in magnitude and opposite in direction.

Let's denote the position of the zero electric field along the line joining the charges as x. There are two possible scenarios:

1. The point is between the charges. In this case, the fields created by the charges are in opposite directions, so we set the magnitudes equal:

kq1/x^2 = kq2/(2-x)^2

Solving this equation for x gives the position of the zero electric field between the charges.

2. The point is outside the charges. In this case, the fields created by the charges are in the same direction, so we set the magnitudes equal and opposite:

kq1/x^2 = kq2/(x-2)^2

Solving this equation for x gives the position of the zero electric field outside the charges.

In both cases, you can cancel out the k in the equations because it appears on both sides. Then you can solve the resulting quadratic equation for x.